All categories

3 years ago

How do you solve 5y+4=4y+5

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

7 0

`•. ¸ (¯ `•. • '¯) ¸. •
`• ¸ • ☆ ° '° ☆ ¸ ¸ ¸ ¸ .... ★ •' ¯` •. -.> ❥
┊ ┊ ┊ * my answer is in the application
┊ ┊ ☆
┊ ★
★

Drupady [299]3 years ago

4 0

Simplifying
5y + 4 = 4y + 5

Reorder the terms:
4 + 5y = 4y + 5

Reorder the terms:
4 + 5y = 5 + 4y

Solving
4 + 5y = 5 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
4 + 5y + -4y = 5 + 4y + -4y

Combine like terms: 5y + -4y = 1y
4 + 1y = 5 + 4y + -4y

Combine like terms: 4y + -4y = 0
4 + 1y = 5 + 0
4 + 1y = 5

Add '-4' to each side of the equation.
4 + -4 + 1y = 5 + -4

Combine like terms: 4 + -4 = 0
0 + 1y = 5 + -4
1y = 5 + -4

Combine like terms: 5 + -4 = 1
1y = 1

Divide each side by '1'.
y = 1

Simplifying
y = 1

You might be interested in

The caffeine content (in mg) was examined for a random sample of 50 cups of black coffee dispensed by a new machine. The mean an

Genrish500 [490]

Answer:

We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 mg .

Step-by-step explanation:

Given -

The sample size is large then we can use central limit theorem

n = 50 ,

Standard deviation $(\sigma)$ = 7.1

Mean $\overline{(y)}$ = 110

$\alpha =$ 1 - confidence interval = 1 - .98 = .02

$z_{\frac{\alpha}{2}}$ = 2.33

98% confidence interval for the mean caffeine content for cups dispensed by the machine = $\overline{(y)}\pm z_{\frac{\alpha}{2}}\frac{\sigma}\sqrt{n}$

= $110\pm z_{.01}\frac{7.1}\sqrt{50}$

= $110\pm 2.33\frac{7.1}\sqrt{50}$

First we take + sign

$110 + 2.33\frac{7.1}\sqrt{50}$ = 112.34

now we take - sign

$110 - 2.33\frac{7.1}\sqrt{50}$ = 107.66

We are 98% confident interval for the mean caffeine content for cups dispensed by the machine between 107.66 and 112.34 .

5 0

3 years ago

What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"

salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is $27 + 64x^{3}$

Now, the equation is $27 + 64x^{3} = 0$

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be $- \frac{3}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.

Again, we have to solve the difference of two cubes which is $64m^{3} - 1$

Now, the equation is $64m^{3} - 1 = 0$

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be $\frac{1}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)

8 0

3 years ago

The standard deviation of a sample taken from population A is 17.6 for a sample of 25. The standard deviation of a sample taken

agasfer [191]

33.3..........................................

3 0

3 years ago

What is 3 over 6 with a negative exponent of 1

kolbaska11 [484]

(3/6)^-1 negative exponent flips the fraction

(6/3)

8 0

3 years ago

Read 2 more answers

If you can exchange 104.51 US dollars for 1,322.14 Mexican pesos, what is the exchange rate of the US dollar to the Mexican peso

Thepotemich [5.8K]

Given:
USD: 104.51
Mexican pesos: 1,322.14

1,322.14 / 104.51 = 12.65

1 US Dollar is equal to 12.65 Mexican Pesos

or

104.51 / 1,322.14 = 0.079

1 Mexican peso is equal to 0.079 US Dollars.

5 0

3 years ago