Answer:
K_a = 8,111 J
Explanation:
This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved
initial instant. Just before dropping the particles
p₀ = 0
final moment
p_f = m_a v_a + m_b v_b
p₀ = p_f
0 = m_a v_a + m_b v_b
tells us that
m_a = 8 m_b
0 = 8 m_b v_a + m_b v_b
v_b = - 8 v_a (1)
indicate that the transfer is complete, therefore the kinematic energy is conserved
starting point
Em₀ = K₀ = 73 J
final point. After separating the body
Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²
K₀ = K_f
73 = ½ m_a (v_a² + v_b² / 8)
we substitute equation 1
73 = ½ m_a (v_a² + 8² v_a² / 8)
73 = ½ m_a (9 v_a²)
73/9 = ½ m_a (v_a²) = K_a
K_a = 8,111 J
1) The object slows down due to kinetic friction.
2) The coefficient of kinetic friction is higher on a carpet than on the bare floor, therefore the object would slow down quicker on the carpet
Answer:
The magnitude of each charge is 
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.
We need to calculate the magnitude of each charge
Using formula of force

Where, q = charge
r = separation
Put the value into the formula




Hence, The magnitude of each charge is 
<h2>Answer: The second Statement
</h2>
<h2>
The algebraic sum of the currents flowing through each of the three resistors is equal to the current through the battery. </h2><h2 />
In a series circuit, the value of the equivalent resistance
is equal to the sum of the values of each of them:
Where:
<h2>The equivalent resistance of the combination of resistors is greater than the resistance of any one of three resistors. </h2>
In this case the current
flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.
Therefore:
<h2>The current flowing through each of the resistors is the same and is equal to the current through the battery. </h2><h2>The algebraic sum of the voltages across the three resistors is equal to the voltage across the battery. </h2>
The battery provides a voltage
that is the sum of the different voltages at the ends of the resistors:
Where the Voltage, according to Ohm's law is:
Hence, the second statement of this question is <u>True
</u>