1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
earnstyle [38]
3 years ago
12

Two students who live on planet X. They want to estimate the circumference. The two students synchronize their watches before on

e student leaves on vacation 600 miles due west to their home. They notice a 3 degree difference in altitude of the sun at local noon. What is the circumference of the planet?
Physics
1 answer:
dexar [7]3 years ago
7 0

Answer:

72000 miles

Explanation:

If the distance between the students is 600 miles, and this implies in a 3 degree difference in the sun position, that means this 600 miles is related to 3 degrees of the circunference of the planet.

So, to find the whole circunference of the planet, that is, 360 degrees, we just need to use a rule of three:

3 degrees -> 600 miles

360 degrees -> x miles

3x = 600 * 360

x = 600 * 360 / 3 = 72000 miles

You might be interested in
Which organisms break down dead matter and waste into nonliving elements?
Alekssandra [29.7K]
Decomposers is the correct answer. ( I got your back bro)
4 0
3 years ago
Read 2 more answers
Dos cargas puntuales están fijas en el eje x: q1 = 6.0µC está en el origen, O, con x1 = 0.0 cm, y q2 = –3.0 µC está situada en e
erik [133]

Answer:

E_total = 1.30 10¹⁰ C / m²

Explanation:

The intensity of the electric field is

     E = k q / r²

on a positive charge proof

The total electric field at the midpoint is

as q₁= 6 10⁻⁶ C the field is outgoing to the right

for charge q₂ = -3 10⁻⁶ C, the field is directed to the right, therefore

E_total = E₁ + E₂

E_total = k q₁ / r₁² + k q₂ / r₂²

r₁ = r₂ = r = 4 10⁻² m

E_total = k/r² (q₁ + q₂)

 we calculate

E_total = 9 10⁹ / (4 10⁻²)²   (6.0 10⁻⁶ +3.0 10⁻⁶)

E_total = 1.30 10¹⁰ C / m²

8 0
3 years ago
A box of mass m1 = 20.0 kg is released from rest at a warehouse loading dock and slides down a 3.0 m-high frictionless chute to
Harrizon [31]

´To develop this problem we will use the concepts related to the conservation of momentum and the application of energy conservation equations to find the velocity of the mass after the collision, like this:

Velocity of the mass m_1 just before the collision

v_1 = \sqrt{2gh}

v_1 = \sqrt{2(9.8)(3)}

v_1 = 7.67m/s

Therefore the momentum just before collision would be

p_2 = m_1v_1+40(0)\\p_1 = 20*7.67+40(0)\\p_1 = 153.36kg \cdot m/s

Momentum after the collision

p_1 = 20*u_1+40u_1\\p_1 = 60u_1

Since the momentum is conserved we have that

153.36= 60u_1

u_1 = \frac{153.36}{60}

u_1 = 2.56m/s

The velocity of mass m_2 after the collision is given by

v_2 = \frac{2m_1}{m_1+m_2} u_1

v_2 = \frac{2(20)}{20+40}(2.56)

v_2 = 1.71m/s

Therefore the change in momentum of mass 2 is

p_2 = m_2v_2

p_2 = 40*1.71

p_2 = 68.4kg\cdot m/s

Therefore the impulse acting on m2 during the collision between the two boxes is p = 68.4kg\cdot m/s

8 0
4 years ago
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
3 years ago
The eccentricity of an asteroid's orbit is 0.0442, and the semimajor axis is 1.12 x 1011 m. The Sun's center is at one focus of
nadezda [96]

Answer:

a. d=99x10^{8}m

b. r=14.22 R_s

Explanation:

The eccentricity of an asteroid's is 0.0442 so

a.

to find the focus distance between both focus is

d=2*e*a

e=1.12x10^{11}m\\a=0.0442

So replacing numeric

d=2*1.12x10^{11}m*0.0442=9900800000

d=99x10^{8}m

b.

Now to find the ratio of that distance between the solar radius and the distance

r=\frac{d_1}{d_s}

r=R_s*\frac{99x10^8m}{6.96x10^8m}

r=14.22 R_s

5 0
4 years ago
Other questions:
  • Indica si las siguientes acciones son el resultado de un efecto estatico o dinamico de una fuerza.
    9·1 answer
  • What is the correct definition of conditioning?
    13·1 answer
  • 1. Why is the theory that all things are made up of atoms a theory and not a fact?
    12·1 answer
  • is a little weird srry A large rock is much heavier than a small water balloon. Yet, you observe that they fall at a similar rat
    7·2 answers
  • The type of tectonic plate boundary that occurs when two plates are colliding into each other is known as a
    9·2 answers
  • CaCO3 is a compound found in cement. Which of the following elements are in CaCO3? calcium carbon oxygen nitrogen copper
    11·1 answer
  • Every few years, winds in Boulder, Colorado, attain sustained speeds of 45.0 m/s (about 100 miles per hour) when the jet stream
    6·1 answer
  • _______ can be generally defined as a change in position. A. Volume B. Force C. Motion D. Mass
    12·2 answers
  • Angel hits a ball with a ball. The action is the ball . What what is reaction force?
    13·1 answer
  • Why should you rotate food when thawing it 360 training?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!