To solve this problem it will be necessary to apply the linear motion kinematic equations plus the law of cosines and sines. This in order to determine the resulting speed and direction of movement. Through the law of cosines we know that the final magnitude of the velocity would be
With the speed found now we can identify the distance traveled, because the displacement was made during a period of 10 minutes at the speed previously found
d = 1770m
The direction of the displacement is found using the law of sines with the velocity triangle
Since the vehicle travels from south to north and from east to west then its deployment will be:
north of due west
Yes, the above-given statement is true
<u>Explanation:</u>
- The product of the mass x the velocity will be the same for both. Momentum is the action of a body with a particular mass through space and there is the conservation of momentum.
- Momentum is described as the mass of the object multiplied by its velocity.
- <u>Momentum (p) = Mass (M) * Velocity (v)</u>
- Therefore for two objects with many masses to have a similar momentum, then the lighter one has to be moving quicker than the heavier object.
Answer:
Explanation:
The acceleration of an object is given by
where
v is the final velocity
u is the initial velocity
t is the time interval it takes for the velocity to change from u to v
For the car in this problem,
u = 21.0 m/s
v = 46.0 m/s
t = 2.5 s
Substituting, we find the acceleration
Answer:
Cost = $ 7.72
Explanation:
Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:
where,
Average Fuel Consumption = 6 liter/100 km
Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter
Distance = 100 km
Therefore,
<u>Cost = $ 7.72</u>
We can obtain the answer easily if we assume the gas here is an ideal gas. We can use t he expression:
PV = nRT
we set nR/V = k
P/T = k
P1/T1 = P2/T2
when P2 = 3P1
P1/10 = 3P1/T2
T2 = 30 degrees Celsius