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Lesechka [4]
3 years ago
13

What mass of potassium hydroxide is formed when 8.2 g of potassium oxide is added to 1.3 g of water? answer key?

Chemistry
1 answer:
stepladder [879]3 years ago
3 0
The reaction occurs by the following equation: 

K20 + H20 = 2KOH 

According to the equation we have following stoichiometric ratio:

n(K2O) : n(H20) = 1 : 1

From it, we can conclude that K2O and water react in same mass ratio.

Now, we have to determine limiting reagent (the one who determines how much the product will arise).

n(K2O)=m/M=8.2/94=0.09 mole

n(H20)=m/M=1.3/18=0.07 mole

So, there are fewer moles of H2O and it will determine the amount of the product.

n(H2O) : n(K0H) = 1 : 2

n(K0H)=n(H2O) x 2 = 0.17 mole

Finally, the was of KOH is:

m(KOH)= n x M = 0.17 x 56= 9.5 g 


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The American Heart Association recommends to eat no more than 2,301mg of sodium per day. Convert the mass of
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The mass of 2,301 grams of sodium in ounces is 0.0811757609 ounces.

The amount of sodium recommended by American heart association is 2301 mg. This limit should not be crossed in a day.

We have to convert Mass of sodium from mg to ounces.

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1 ounce = 28.3459 grams.

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28.3459 grams = 28.3459 x 1000 milligrams.

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Mass of sodium in ounces is 0.0811757609.

To know more about Unit conversion, visit,

brainly.com/question/97386

#SPJ9

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