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2 years ago

What mass of potassium hydroxide is formed when 8.2 g of potassium oxide is added to 1.3 g of water? answer key?

1 answer:

3 0

The reaction occurs by the following equation:

K20 + H20 = 2KOH

According to the equation we have following stoichiometric ratio:

n(K2O) : n(H20) = 1 : 1

From it, we can conclude that K2O and water react in same mass ratio.

Now, we have to determine limiting reagent (the one who determines how much the product will arise).

n(K2O)=m/M=8.2/94=0.09 mole

n(H20)=m/M=1.3/18=0.07 mole

So, there are fewer moles of H2O and it will determine the amount of the product.

n(H2O) : n(K0H) = 1 : 2

n(K0H)=n(H2O) x 2 = 0.17 mole

Finally, the was of KOH is:

m(KOH)= n x M = 0.17 x 56= 9.5 g

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Answer:

3,048 minutes

Explanation:

762 divided by 5

that number times 20

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2 years ago

In ocean water, salt is a(n) _____. a. solution b. alloy c. solvent d. solute

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2 years ago

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6. What is the wavelength (in meters) of the electromagnetic carrier wave transmitted by The Sports

Vsevolod [243]

Answer:

wavelength = 2.81 m

Explanation:

Given that,

The frequency of the Sports Fan radio station, f = 106.4 MHz

We need to find the wavelength (in meters) of the electromagnetic carrier wave. The relation between frequency and wavelength is given by :

$c=f\lambda$

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2 years ago

7. How many chlorine atoms are in a 34.2 g sample of dichlorine pentoxide?

Reptile [31]

Answer:

The answer to your question is 1.36 x 10²³ atoms

Explanation:

Data

number of atoms = ?

mass of the sample = 34.2 g

Molecule = Cl₂O₅

Process

1.- Calculate the molar mass of Cl₂O₅

Cl₂O₅ = (35.5 x 2) + (16 x 5) = 71 + 80 = 151 g

2.- Calculate the atoms of Cl₂O₅

151 g of Cl₂O₅ ---------------- 6 .023 x 10²³ atoms

34.2 g of Cl₂O₅ ------------ x

x = (34.2 x 6.023 x 10²³) / 151

x = 1.36 x 10²³ atoms

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3 years ago

Calculate the volume of compound Y needed to make a 350 pg/ml treatment solution in 2 ml of 1x PBS using a stock solution contai

harina [27]

Answer:

14 mL

Explanation:

To prepare a solution by a concentrated solution, we must use the equation:

C1xV1 = C2xV2, where C is the concentration, V is the volume, 1 is the initial solution and 2 the final solution.

The final solution must have 2 mL and a concentration of 350 pg/mL, and the initial solution has a concentration of 50 pg/mL.

Then:

50xV1 = 350x2

50xV1 = 700

V1 = 700/50

V1 = 14 mL

4 0

3 years ago