As,
CuCO₃ ⇆ Cu²⁺ + CO₃²⁻
So,
Kc = [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
Kc (CuCO₃) = [Cu²⁺] [CO₃²⁻]
Or,
Ksp = [Cu²⁺] [CO₃²⁻]
As,
Ksp = 1.4 × 10⁻¹⁰
So,
1.4 × 10⁻¹⁰ = [x] [x]
Or,
x² = 1.4 × 10⁻¹⁰
Or,
x = 1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
x = 1.18 × 10⁻⁵ mol/L × 123.526 g/mol
x = 1.45 × 10⁻³ g/L
N=m/M
n=118/58.93=2
Answer: 2 moles
Pretty sure it's b but not an definitely
Answer:
1.52 L
Explanation:
P1V1T2=V2P2T1
V2=V1T2/T1
Fill in with given values then solve
We can check this by knowing that V and T at constant P have a proportional relationship. Hence, this is correct.
- Hope that helped! Please let me know if you need further explanation.
