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lutik1710 [3]
3 years ago
11

Julia wants to find out which color fabric will heat up the fastest when put under a direct light.

Chemistry
2 answers:
drek231 [11]3 years ago
3 0
NO the answers wont be valid.
Readme [11.4K]3 years ago
3 0

Answer:

no to many variables

Explanation:

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According to the reaction represented by the unbalanced equation above, how many moles of so2(g) are required to react completel
melomori [17]
2SO₂ + O₂ = 2SO₃

n(O₂)=1 mol

n(SO₂)=2n(O₂)

n(SO₂)=2 mol
6 0
3 years ago
Which of these elements is essential to making up all of the organic molecules?
siniylev [52]
Carbon

Hope this helps (:
5 0
3 years ago
Read 2 more answers
What is a Cilla ? What does it look like ? (In drawing )
vova2212 [387]

a short microscopic hairlike vibrating structure found in large numbers on the surface of certain cells.

Explanation:

either causing currents in the surrounding fluid, or, in some protozoans and other small organisms, providing propulsion.

3 0
3 years ago
What coefficient should be used to make the following equation balanced? N2+O2--> _NO
IgorLugansk [536]
<h2>                  ║∧║······→Hello.←······║∧║</h2>

                                          Your answer should be:

                                                N2 + O2 → 2NO

<h2>····················································································</h2>

I hope this answered your question!

Thanks for spending time reading this :)

(<em>A brainliest would be appreciated!)</em>

⊕If this answer doesn't answer your question or you are displeased by it please tell me in the comments I would like to know. And if I can, I will remove it.⊕

<h2>Have a wonderful day</h2>
7 0
2 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
2 years ago
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