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3 years ago

If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?

Chemistry

1 answer:

Gwar [14]3 years ago

5 0

Answer:

only 2.5 grams will be present after 16 years have passed

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How many particles are present in 8.0 moles of silver?

Zielflug [23.3K]

Answer:the answer is b

Explanation:I took the test and got it right

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3 years ago

Explain using the particles theory what happens when steam in the bathroom hits a cold surface such as a mirror

Aleks04 [339]

The fog in the mirror is the condensation of water vapor as it touches a colder surface. When you are running cold water you just cool down everything around it. Now the vapor coming from the hot shower will mostly condense right there and will not reach the mirror.

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3 years ago

Matter is made up of heat energy and ___________energy?

ella [17]

You’re correct, matter is made up of heat energy and chemical energy

all matter contains heat because it is the result of the movement of atoms, molecules, or ions in solids, liquids, and gases.

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2 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

Answer: The mass of original oxalic acid sample is 6.75 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

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2 years ago

One of the most difficult solar energy design problems to solve is:

Sonja [21]

I'm not sure but i would say C.storing the heat energy.

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3 years ago

Read 2 more answers