Question

If you have 4.00 gg of H2, how many grams of NH3 can be produced?

Answer 1

Answer:

22.49 g of NH3

Explanation:

The balanced equation for this would be:

3H₂+N₂ → 2NH₃

So let's take note of this:

We will need 3 moles of H₂ to produce 2 moles of NH₃.

Now let us convert:

First we determine the molar mass of H2:

Element:

     number of atoms   x     molar mass

H   =          2                 x       1.01 g/mol = 2.02 g/mol

Let's see how many moles of H2 there are in 4.00g

$4.00 g\times \dfrac{1\;mole\;of\;H_2}{2.02g} = 1.98\;moles\;of\;H_2$

Now we can see how many moles of NH₃ we can make given the ratio and convert it again to grams by getting the molar mass of NH₃:

$1.98\;moles\;of\;H_2\times\dfrac{2\;moles\;of\;NH_3}{3\;moles\;of\;H_2} = 1.32\;moles\;of\;NH_3$

This means that with 1.98 moles of H₂, we produce 1.32 moles of NH₃

So let's get the molar mass of NH₃ so we can convert it to grams:

N      =   1 x 14.01 = 14.01

H      =  3 x 1.01   = 3.03

                             17.04g/mol

$1.32\;moles\;of\;NH_3\times\dfrac{17.04g\;of\;NH_3}{1\;mole\;of\;NH_3} = 22.49g\;of\;NH_3$