3 years ago

What is the HORIZONTAL component of a vector with a magnitude of 125 m/s and an angle of 25 degrees?

Physics

1 answer:

Vlad1618 [11]3 years ago

6 0

Answer:

113.29 m/s

Explanation:

I think its this answer choice, hope I'm not too late answering.

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3 years ago

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kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, $h_{max}$ , is given by the following equation;

$h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}$

Therefore, substituting the known values for the pebble, we have;

$h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439$

Therefore, the maximum height of the pebble projectile, $h_{max}$ ≈ 6.4 m.

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3 years ago

Hi Guys.I was just wondering if given two specific heat capacities (In my case copper and water) do you add them both together o

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Answer:

yes

Explanation:

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2 years ago

The temperature of a small metal cube is 75°c. A student places the cube into an insulated container of water at a temperature o

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