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timurjin [86]
3 years ago
11

Carlos is buying milk. he needs 3 liters. A​ half-liter of milk costs ​$2.16. A ​200-milliliter container of milk costs ​$1.17.

What should Carlos buy so he gets 3 liters at the lowest​ price?
Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

The 1/2 liter option ($12.96)

Step-by-step explanation:

Info Given

  • Carlos needs 3 liters of milk
  • 1/2 liter of milk costs $2.16
  • 200 ml container of milk costs 1.17
  • 200 ml = 0.2 liters

12.96 = Total of 3 liters of milk with the 1/2 liter amount

17.55 = Total of 3 liters of milk with the 200 ml amount

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A rectangular box is to have a square base and a volume of 72 ft3. If the material for the base costs $0.62/ft2, the material fo
Igoryamba

Answer:

a. length  = 0.7211 ft

b. width  = 0.7211 ft

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Step-by-step explanation:

This is an optimiztion with restriction problem.

We have to minimize the cost, with the restriction of the volume being equal to 72 ft3.

As the cost for the sides is constant, we know that length and width are equal.

Then, we can express the volume as:

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We can express the height in function of the length as:

x^2z=73\\\\z=73x^{-2}

Then, the cost of the box can be expressed as:

C=0.62(x^2)+4*0.15(xz)+0.18(x^2)=(0.62+0.18)x^2+0.60xz\\\\C=0.8x^2+0.60x*x^{-2}=0.8x^2+0.6x^{-1}

To optimize C, we derive and equal to zero

\dfrac{dC}{dx}=\dfrac{d}{dx}[0.8x^2+0.6x^{-1}]=1.6x-0.6x^{-2}=0\\\\\\1.6x=0.6x^{-2}\\\\x^{1+2}=0.6/1.6=0.375\\\\x=\sqrt[3]{0.375} =0.7211

The height z is then

z=73x^{-2}=\dfrac{73}{0.7211^2}=\dfrac{73}{0.52}=140.3846

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