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Dahasolnce [82]
3 years ago
14

Carbon show some unique property name them name them​

Physics
1 answer:
swat323 years ago
6 0

Answer:

Physical Properties of Carbon:

Carbon is a unique element. It occurs in many forms. Some examples of the pure form of carbon are coal and soot.

It is soft and dull grey or black in colour.

One of the most important compounds of carbon is the charcoal, which is formed when carbon is heated in the absence in of air.

It occurs in a number of allotropic forms. Allotropes are nothing but forms of an element with varying physical as well as chemical properties.

The density of the different forms of carbon depends upon the origin of these elements. You will find some forms of carbon which are pure and some forms which are not pure like coal which is the mixture of both carbon and hydrogen.

Chemical Properties of Carbon

Carbon compounds generally show 4 reactions, they are

Combustion reaction

Oxidation reaction,

Addition reactions

Substitution reaction.

As we all know that carbon in all forms needs oxygen, heat, and light and forms carbon dioxide. When it is burned in air to give carbon dioxide, it is called as combustion.

Let us get the concept of this using some examples when it is burnt in the air: When methane CH4 is burnt in the presence of oxygen it gives us carbon dioxide, heat, and light.

Explanation:

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Calculate the pressure due to sea water as density*depth.
That is, 
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Atmospheric pressure is  101.3 kPa
Total pressure is  94423 + 101.3 = 94524 kPa (approx)

The area of the window is π(0.44 m)^2 = 0.6082 m^2

The force on the window is
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For all turning vehicles, the rear wheels follow a ______ than the front wheels.
aliya0001 [1]

Answer:

Shorter path

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For all turning vehicles, the rear wheels follow <u>Shorter path</u> than the front wheels.

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Why can an object still be seen when it is at absolute zero?
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A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
zloy xaker [14]

Solution :

Given :

Mass attached to the spring = 4 kg

Mass dropped = 6 kg

Force constant = 100 N/m

Initial amplitude = 2 m

Therefore,

a). $v_{initial} = A w$

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Now, $\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$

A' = amplitude = 1.4142 m

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  $=\frac{1}{2}$

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