The answer is A. Friction
hope this helps :)
Answer:
<h3>30m/s</h3>
Explanation:
acceleration is the change in velocity of a body with respect to time
a = v-u/t
v is the final velocity
u is the initial velocity = 10m/s
t is the time taken = 10s
a is the acceleration = 2m/s²
substitute the values into the formula
2 = v-10/10
cross multiply
20 = v-10
v = 20+10
v = 30m/s
Hence the velocity of the body after 10s is 30m/s
Answer:
a) please find the attachment
(b) 3.65 m/s^2
c) 2.5 kg
d) 0.617 W
T<weight of the hanging block
Explanation:
a) please find the attachment
(b) Let +x be to the right and +y be upward.
The magnitude of acceleration is the same for the two blocks.
In order to calculate the acceleration for the block that is resting on the horizontal surface, we will use Newton's second law:
∑Fx=ma_x
T=m1a_x
14.7=4.10a_x
a_x= 3.65 m/s^2
c) <em>in order to calculate m we will apply newton second law on the hanging </em>
<em> block</em>
<em> </em>∑F=ma_y
T-W= -ma_y
T-mg= -ma_y
T=mg-ma_y
T=m(g-a_y)
a_x=a_y
14.7=m(9.8-3.65)
m = 2.5 kg
<em>the sign of ay is -ve cause ay is in the -ve y direction and it has the same magnitude of ax</em>
d) calculate the weight of the hanging block :
W=mg
W=2.5*9.8
=25 N
T=14.7/25
=0.617 W
T<weight of the hanging block
Answer:
the four seasons would each be twice as long as they are now
Explanation:
A year is the result of the Earths revolution around the sun i.e., the Earth takes 365 days to complete one revolution around the sun. A day is the result of the Earth's rotation on its axis i.e., it takes 24 hours for Earth to complete one rotation on its axis.
The Earth is titled by about 23.5 degrees, this results in the seasons of Earth. The distance from the sun has nothing to do with the seasons. During the northern hemisphere winter the Earth is actually closer to the sun than in the summer. So, if our year was twice as long then the seasons would be twice as long.
Over the first 30.0 s, the undergoes a displacement of
(12 m/s) * (30.0 s) = 360 m
Over the next 8.00 s, the car accelerates from 12 m/s to a top speed of
12 m/s + (1.5 m/s²) * (8.00 s) = 24 m/s
and over this time interval, it is displaced an additional
(12 m/s) * (8.00 s) + 1/2 (1.5 m/s²) * (8.00 s)² = 144 m
For the last 12.0 s, the car moves at a constant speed of 24 m/s to cover a distance of
(24 m/s) * (12.0 s) = 288 m
So the car's net displacement is 360 m + 144 m + 288 m = 792 m. (The net displacement is the same as distance in this case because the car moves in only one direction.)
