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Paraphin [41]
3 years ago
5

I need help please anyone

Physics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

C.

Explanation:

The velocity is going down at the beginning of Carla's trip, so acceleration is decreasing; this means she was slowing down. Then, the line hits 0, which means she isn't moving. Then, she started moving again after 4 seconds, so she was speeding up.

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The first car has twice the mass of a second car, but only half as much kinetic energy. When both cars increase their speed by 9
kirill [66]

Answer:

Speed of the car 1 =V_1=8.98m/s

Speed of the car 2 =V_2=17.96m/s

Explanation:

Given:

Mass of the car 1 , M₁ = Twice the mass of car 2(M₂)

mathematically,

M₁ = 2M₂

Kinetic Energy of the car 1 = Half the kinetic energy of the car 2

KE₁ = 0.5 KE₂

Now, the kinetic energy for a body is given as

KE =\frac{1}{2}mv^2

where,

m = mass of the body

v = velocity of the body

thus,

\frac{1}{2}M_1V_1^2=0.5\times \frac{1}{2}M_2V_2^2

or

\frac{1}{2}2M_2V_1^2=0.5\times \frac{1}{2}M_2V_2^2

or

2M_2V_1^2=0.5\times M_2V_2^2

or

2V_1^2=0.5\times V_2^2

or

4V_1^2= V_2^2

or

2V_1= V_2  .................(1)

also,

\frac{1}{2}M_1(V_1+9.0)^2=\frac{1}{2}M_2(V_2+9.0)^2

or

\frac{1}{2}2M_2(V_1+9.0)^2=\frac{1}{2}M_2(2V_1+9.0)^2

or

2(V_1+9.0)^2=(2V_1+9.0)^2

or

\sqrt{2}(V_1+9.0)=(2V_1+9.0)

or

(\sqrt{2}V_1+ \sqrt{2}\times 9.0)=(2V_1+9.0)

or

(\sqrt{2}V_1+ 12.72)=(2V_1+9.0)

or

(2V_1-\sqrt{2}V_1)=(12.72-9.0)

or

(0.404V_1)=(3.72)

or

V_1=8.98m/s

and, from equation (1)

V_2=2\times 8.98m/s = 17.96m/s

Hence,

Speed of car 1 =V_1=8.98m/s

Speed of car 2 =V_2=17.96m/s

8 0
3 years ago
Read 2 more answers
The question on science please answer correctly
umka2103 [35]
The 5kg object 5m/s 1 m off the ground
3 0
3 years ago
A roller coaster car travels up and down the hills of its track. Neglecting
Volgvan

Answer:

option D is the correct option

Must always remain constant

Explanation:

According to their law of conservation of energy :it states that in a closed system,the total mechanical energy is always constant although energy may change from one form to another. e. g from potential energy to kinetic energy

7 0
3 years ago
A helium–neon laser emits a beam of circular cross section with a radius r and a power P.?. (a) Find the maximum electric field
olchik [2.2K]

there is a relation between intensity of light beam and the magnitude of electric field.<span>I=(1/2)c<span>ϵo</span>n<span>E2</span>=P/π<span>r2</span></span> <span><span>E2</span>=2P/c<span>ϵo</span>nπ<span>r2</span></span> E= magnitude of electric field n= refractive index of medium <span><span>μo</span><span>ϵ0</span>=1/<span>c2
</span></span>energy= power*time = P*(1m/speed of light)<span><span>energy=(P∗1m)/c</span></span>
5 0
4 years ago
If a car is traveling eastward, can its acceleration be westward?
KATRIN_1 [288]
Yes it can. It may be a bit counterintuitive but if the car is slowing down, even if it's traveling east, its acceleration is toward the west because it's decelerating and slowing down.
5 0
3 years ago
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