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FromTheMoon [43]
3 years ago
5

The length of a rectangle is 11 inches longer than it's width, the perimeter is 86 inches write an equation and solve to find le

ngth
Mathematics
1 answer:
olga_2 [115]3 years ago
6 0
I have no clue soooo sorry

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The length of a rectangle is the sum of the width and 2. The area of the rectangle is 48 units. What is the length, in units, of
suter [353]

Length of the rectangle is 8 units

Step-by-step explanation:

  • Step 1: Find the length, let width be x.

Area of the rectangle = 48 units

Length = x + 2

⇒ Area = Length × Breadth

48 = x (x + 2)

48 = x² + 2x

x² + 2x - 48 = 0

x² + 8x - 6x + 48 = 0 (Product Sum rule to factorise)

x(x + 8) - 6(x + 8) = 0

(x - 6)(x + 8) = 0

⇒ x = 6, -8 (negative value is neglected)

∴ x = 6

x + 2 = 8

6 0
3 years ago
Explain how you can tell the function f (x) = |x + 4| is not linear by using points on its graph.
zhannawk [14.2K]

If there are any three points on the graph that are not on the same line, the function is nonlinear. Such points might be ...

... (-5, 1), (-4, 0), (-3, 1)

6 0
3 years ago
Which equation represents the graph?
klio [65]
The second option.

That is because
y -3 = - \frac{1}{2}(x + 1) \\ (y -3)+3 = (- \frac{1}{2} x - \frac{1}{2}) + 3 \\ y = - \frac{1}{2}x + 2 \frac{1}{2}
6 0
3 years ago
1. A supermarket display consists of boxes of soda. The bottom row has 38 boxes. Each row has four fewer boxes than the row belo
Andreas93 [3]

Answer:

10 boxes in the top row.

192 boxes in entire display.

Step-by-step explanation:

Let n be the number of rows.

Given:

Total number of rows = 8

Boxes in bottom row = 38

And each row has four fewer boxes than the row below it.

Solution:

Part A:

We know that the bottom row has 38 boxes and each row has four fewer boxes than the row below it.

Using below function for determining the number of boxes in each rows.

f(n)=38-(8-n)4

Where:

n = Number of row.

We need to find the boxes in the first row.

So, substitute n = 1 in above function.

f(1)=38-(8-1)4

f(1)=38-7\times 4

f(1)=38-28

f(1)=10

Therefore, 10 boxes in the top row.

Part B:

Total boxes in the entire display.

Using formula as given below to determine the sum of the boxes in entire display.

S_{n} = \frac{n}{2}(f(1)+f(n))

Substitute n = 8, f(1) = 10 and f(8) = 38 in the above equation.

S_{8} = \frac{8}{2}(10+38)

S_{8} = 4(48)

S_{8} = 4\times 48

S_{8} = 192\ boxes

Therefore, 192 boxes in the entire display.

5 0
3 years ago
Second part of the problem find the x. <br><br> Link: https://brainly.com/question/26290433
Sliva [168]

Answer:

no

Step-by-step explanation:

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