Your function is not defined at x=0 and x=4 (you have vertical asymptotes there). So, the denominator must be zero at x=0 and x=4. This is the case for

So, the function with that denominator is graphed.
First you should find the area of the rectangle in the middle.
A: 9 x 6 = 54
Then you can find the area of the triangle on the right.
A: 6 x 5 = 30/2 = 15
Then you can do the triangle on the right.
11-9 = 2
A: 2 x 6 = 12/2 = 6
Then you can add it all together.
15 + 6 + 54 = 74
So the area of the irregular shape is 74.
I hope this helps!
Answer:
30 SQUARE units
Step-by-step explanation:
Since the problem only includes two dimensions, we solve for area, not volume. Area=width*height, or 3*10=30. Because we're solving for area the answer is 30 square units.
Answer
x-19=27
Step-by-step explanation:
the standard equation of the circle having the given center and radius is
.