Elements in the same group<span> in the </span>periodic table<span> have </span>similar<span> chemical properties. This is because their atoms have the </span>same<span> number of electrons in the highest occupied energy level. </span>Group<span> 1 </span>elements<span> are reactive metals called the alkali metals.</span>Group<span> 0 </span>elements<span> are unreactive non-metals called the noble gases.</span>
1 mole of reacts with 8 moles of to form 1 mole of and 3 moles of
<h3>What is a tetraphosphorus decoxide?</h3>
Tetraphosphorus decoxide, () is a non-metal oxide that gives acidic property when dissolved in water.
The name phosphorus decoxide can be interpreted as 4 phosphorus (P) atoms (‘Tetra’), bonds with 10 oxygen (O) atoms (‘Dec’) in a molecule. besides that, it is also known as phosphorus pentoxide.
It can be prepared by heating pure phosphorus with oxygen in blast furnace.
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It is used as a dehydrating agent due to its week van der Waals dispersion forces. Thus, owing to give exothermic reaction when dissolved in watermore precisely, it is a white crystalline anhydrous (without water molecule) solid.
In granular form it can be also used as desiccant as well.
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Answer:
Explanation:
As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.
Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>
So, you must just convert the given temperature, 32°F, to kelvin scale.
You can do that in two stages.
- First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80
- Second, convert 0°C to kelvin:
T (K) = T(°C) + 273.15 K= 273.15 K
Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K
Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.
Yes it is available. It will continue catalyzing the reactions until it becomes completely consumed. That's how enzymes work. They work and are eventually consumed in the process completely without altering the reaction in any way other than speeding it up.
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Answer:
FeSO2
Explanation:
Please see attached picture for full solution.
