Answer:
128 grams of sulfur dioxide are produced.
Explanation:
Moles of HCl = 4 moles
According to reaction, 2 moles of HCl gives 1 mole of sulfur dioxide gas.
Then 4 moles of HCl will give:
of sulfur dioxide gas.
Mass of sulfur dioxide gas = 2 mol × 64 g/mol = 128 g
128 grams of sulfur dioxide are produced.
Answer:
Moles of NaOH that reacted:
Explanation:
During the titration, all moles of NaOH added in the solution, react with the acetylsalicylic acid neutralizing each other.
The titration required 15.62 ml (0.01562 L) of the 0.1052 M NaOH solution. The moles of NaOH in that volume are:
<u>Answer:</u> The volume of oxygen gas required is 3.75 mL
<u>Explanation:</u>
STP conditions:
1 mole of a gas occupies 22.4 L of volume.
We are given:
Volume of ammonia reacted = 3.00 mL = 0.003 L (Conversion factor: 1 L = 1000 mL)
The chemical equation for the reaction of ammonia with oxygen follows:
By Stoichiometry of the reaction:
(4 × 22.4) L of ammonia reacts with (5 × 22.4) L of oxygen gas
So, 0.003 L of ammonia will react with = of oxygen gas
Hence, the volume of oxygen gas required is 3.75 mL