Answer:
Explanation:
Just as context, write the chemical equation and the mole ratios
1) <u>Balanced chemical equation</u>:
- CuO (s) + H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)
2) <u>Therotetical (stoichiometric) mole ratios</u>:
- 1 mol CuO : 1 mol H₂SO₄ : 1 mol CuSO₄ : 1 mol H₂O
You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield
3) <u>Percent yield</u>
Percent yield = (actual yield / theoretical yield)×100
- Theoretical yiedl (given): 3.19 moles CuSO₄
- Actual yield (given): 2.50 moles CuSO₄
Substitute the values in the formula:
- Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%
D. In a Chemical reaction, elements are not changed, just rearranged. Small amounts of energy take place.
Answer:
a.
9.88
Explanation:
ΔG = - 2.303 RT log Ka
ΔG is change in free energy at temperature T , Ka is equilibrium constant
- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa
- log Ka = 9.88 .
pKa = 9.88 .
D. similar number of nuetrons
I really hope and think it’s E