Answer:
The savings of Sid and Tim will be in 17:9 in 6 weeks.
Step-by-step explanation:
Initial savings of Sid = £ 13
Initial savings of Tim = £ 0
For each successive week Sid saved = £ 3.5
For each successive week Tim saved = £ 3
Let us assume that after "x weeks" the amounts of Sid and Tim are in ratio 17:9.
If Sid saves £ 3.5 in one week, in x weeks he will £ 3.5x. Since he had £ 13 initially, total amount he would have in x weeks will be £ (13 + 3.5x)
If Time saves £ 3 one week, in x weeks he will save £ 3x. Since, he didn't have any money initially, in x weeks he would have saved £ 3x
The ratio of their savings in x weeks would be 17:9
So,
Sid's saving : Tim's saving = 17 : 9
Using the values of expressions, we get:
This means, the savings of Sid and Tim will be in 17:9 in 6 weeks.
Answer:
66.6% or 0.66
Step-by-step explanation:
82% or 0.82 of All households have cable TV.
X = The number of households in a group of 6, that have cable TV.
You wish to find the proportion or percentage of groups for which EXACTLY 4 of 6 households will have cable TV.
82% of 6 is = 4.92
Approximately 4.92 out of 6 households, have cable TV.
Using this figure, you can now find out what % of 6 will give you 4.
Cross multiply:
0.82 - 4.92
M - 4
M = (4×0.82) ÷ 4.92 = 3.28÷4.92 = 0.666
Hence, 66.6% of 6 households, have cable TV. In other words, exactly 4 households (X=4) have cable TV.
To test, you can find what 66% of 6 is. You will get 4.
Step-by-step explanation:
To write 5 as a fraction with a common denominator, multiply by 55 . Combine 5 and 55 . Combine the numerators over the common denominator. Simplify the numerator.
<h3>Answers:</h3>
The probability of not drawing a red marble is 7/10
The probability of drawing a red marble is 3/10
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Explanation:
We have 3 red marbles out of 5+2+3 = 10 total. Therefore, the probability of selecting a red marble is 3/10.
The probability of not selecting a red marble is 7/10 because 3/10+7/10 = 1. Put another way, we have 7 marbles that aren't red (the 5 blue and 2 black ones) out of 10 total.
