So,
#1:

Convert to like improper fractions.

Add.

So, one solution could be

.
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2:

Convert into improper fraction form.

Multiply.

Cross-cancel, and we have our final result.

k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
AABC has vertices at (1,5), (4,8), and (16, 12). A second triangle, ADEF, has vertices at (4, 20), (16, 32), and (64, 48). If th
navik [9.2K]
Answer: the first one
Step-by-step explanation:
(x,y)->(4x, 4y)
So first do 3(x+1) which is 3x+3 because you have to multiply the outside number by the stuff in side the parentheses. Then you do the 5(x-2)+7 and it should be 5x-10+7 so now your equation should be 3x+3=5x-10+7 now subtract the 3x from the 5x and now your equation should look like this: 3=2x-10+7. Then you add the 10 and the 7 so now your equation should look like this: 3=2x-3 because it's a -10 and a positive 7 it would be -3. So then you have to add the -3( which now becomes positive to the other 3 in front of the = sign. So now your equation should look like this: 6=2x. Now divide by 2 to get x by its self and now your answer should be 3=x or x=3.
So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.
A. (2,0) (0,-3)
B. slope= 3/2
C. y= 3/2x-3
D. 3/2x+y= -3