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Lemur [1.5K]
4 years ago
13

Is the quotient of two rational numbers always a rational number? Explain.

Mathematics
1 answer:
Natasha_Volkova [10]4 years ago
6 0

Answer:

Yes,

Step-by-step explananation

The quotient of two rational numbers is always rational, and the reason for this lies in the fact that the product of two integers is always an rational number.

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Which polynomial correctly combines the like term and express the given polynomial in standard form
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Answer:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

Step-by-step explanation:

Given

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3

Required

Correctly combine the like terms

We have:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3

Collect like terms (in decreasing degrees of m)

- 2m^6 - 4m^6  - mn^5- m^3n^3  - 4m^3n^3+ 5m^2n^4  + 9m^2n^4 + 8mn^5  + n^6

-6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

So:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

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