Answer:
5.3 mol CO₂
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
3.2 × 10²⁴ molecules CO₂
<u>Step 2: Convert</u>
<u /> = 5.31385 mol CO₂
<u>Step 3: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
5.31385 mol CO₂ ≈ 5.3 mol CO₂
Do you know how to break it down?
If the concentration of cholesterol is 238mg/100ml:
238 mg ==> 100ml
2380 mg (or 2.38g) ==> 1000ml (1L)
So the concentration will be 2.38 g/L of cholesterol.
if the volume is 5.2 L, the total grams of cholesterol would be :
m = C . V = 2.38g/L * 5.2 L = 12.376 grams of cholesterol.
<em>Acetic acid, HC2H3O2</em>
First, calculate for the molar mass of acetic acid as shown below.
M = 1 + 2(12) + 3(1) + 2(16) = 60 g
Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
P1 = ((4)(1)/60)(100%) = <em>6.67%</em>
<em> Carbon:</em>
P2 = ((2)(12)/60)(100%) = <em>40%</em>
<em>Oxygen</em>
P3 =((2)(16) / 60)(100%) = <em>53.33%</em>
<em>Glucose, C6H12O6</em>
The molar mass of glucose is as calculated below,
6(12) + 12(1) + 6(16) = 180
The percentages of the elements are as follow,
<em> Hydrogen:</em>
P1 = (12/180)(100%) = <em>6.67%</em>
<em>Carbon:</em>
P2 = ((6)(12) / 180)(100%) = <em>40%</em>
<em>Oxygen:</em>
P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>
b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal.