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Grace [21]
3 years ago
12

6. Which of the following indicates that a chemical change has happened during cooking?

Chemistry
1 answer:
Crazy boy [7]3 years ago
5 0

Answer: bubbles form in boiling water

Explanation:

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A 5.50 gram sample of C2H6 gas has a volume of 2.50 L. If the sample is at 41.20C, what will it’s pressure be?
vovangra [49]
Multiple them divided by 2.50
8 0
3 years ago
SOICHIOMETRY HOW MANY MOL OF NITROGEN DIOXIDE ARE REQUIRED TO PRODUCE 2.75 MOL NITRIC ACID? 3NO2+ H20→ 2HNO3+ NO
pishuonlain [190]

Answer: C

Explanation: Hope this help :D

4 0
3 years ago
What is the mass number of the isotope zinc – 65?<br><br> a.30<br> b.65<br> c.35<br> d.95
aliina [53]
Atomic mass <span>of zinc ( zn ) is 65 u

Answer B</span>
3 0
3 years ago
A body moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. How far does the body move in 5 seconds?
Norma-Jean [14]
The distance covered will be:

d = v_0\cdot t + \frac{1}{2}a\cdot t^2 = 20\frac{m}{s}\cdot 5\ s + \frac{5}{2}\frac{m}{s^2}\cdot 5^2\ s^2 = \bf 162,5\ m

The correct answer is D).
8 0
3 years ago
Read 2 more answers
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
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