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2 years ago

Which shows the correct relationship?

Chemistry

2 answers:

erastova [34]2 years ago

7 0

Answer: B.) $E^0_{cell}$ > 0 = spontaneous reaction

Explanation:

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G=-nFE^0$

$\Delta G$ = gibbs free energy

n= no of electrons gained or lost

F= faraday's constant

$E^0$ = standard emf

when $\Delta G$ = +ve, reaction is non spontaneous

$\Delta G$ = -ve, reaction is spontaneous

$\Delta G$ = 0, reaction is in equilibrium

Thus reaction is spontaneous when $E^0$ = +ve

Thus reaction is non spontaneous when $E^0$ = -ve

Thus reaction is in equilibrium when $E^0$ = 0.

Andrews [41]2 years ago

4 0

I think the correct answer from the choices listed above is option B. The correct relationship would be Eo cell > 0 = spontaneous reaction. For a spontaneous reaction, Ecell is positive and ΔG (Gibbs free energy, used to determine if a reaction occurs spontaneously) is negative. Hope this answers the question.

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2 years ago

Draw the structure of bromous acid, hbro2. optimize formal charges.

ArbitrLikvidat [17]

STRUCTURE OF BROMOUS ACID: H–O–Br=O

In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below: 

H: 1 – 1/2(2) – 0 = 0
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3 years ago

2.0 kg of carbon is heated from 25°C to 55°C, and absorbs 42600 joules of heat in the process.

Marrrta [24]

Answer: c = 710 J/kg°C or 0.71 J/g°C

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c = Q / m∆T

= 42600 J / 2 kg ( 55°C - 25°C )

= 710 J /kg°C

Or can be expressed by converting kg to g.

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6 0

2 years ago

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The element hydrogen adom is made up of wich kinds of adams

egoroff_w [7]

the element hydrogen atom is made up of oxygen atoms.

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2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

2 years ago

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