Answer:
237.5 K.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 5.2 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = 4.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = ??? K).
∴ T = PV/nR = (5.2 atm)(15.0 L)/(4.0 mol)(0.0821 L.atm/mol.K) = 237.5 K.
Answer:
When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature
Explanation:
<span>Density = mass / volume
3.32 kg = 3320 g
volume mass / density
3320 / 1.11 = 2990.99</span>
Answer:
To calculate the number of significant figures in a number with decimal,
start at the first non-zero digit in the number and count the total number of digits till the end
hence, in this number:
we will have 6 significant figures
Answer:
Explanation:
I'm not sure what is being asked, not the units of "1.5." I don't know of potassium "ioxicide." Was "dioxide" intended?
I'll assume the question is "What is the concentration, in Molar, of 1.5g of potassium dioxide in 150cm^3 of water (150cm^3 is 150 ml).
The molar mass of K2O, potassium dioxide, is 94.2 g/mole. 1.5g is (1.5g/94.2 g/mole) or 0.0159 moles of K2O. The definition of Molar is moles/liter. So take the moles of K2O and divide by the liters, which is 0.150L in this case.
(0.0159 moles K2)/0.150 L = 0.106 M K2O
