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3 years ago

In which situation is maximum work considered to be done by a force?

Chemistry

1 answer:

Lelu [443]3 years ago

6 0

Answer:

Option E

Explanation:

As work is dot product of force and displacement

W=FdCos0

As Cos 0=1 so W=F.d(1)

W=F.d

as Cos 90=0 so no work will be done when angle between force and displacement is 90 degree. At angle between force and displacement is 180 degree then negative value com as Cos 180= -1

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Which of the following would

nadezda [96]

Answer: A forest

Explanation:

Moss are more likely to be found in moist shady locations. They are best known for those species that carpet woodland and forest floors.

4 0

2 years ago

A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3100

inessss [21]

Answer:

82.59 m/s or 297.324 km/h

Explanation:

From the question,

Applying

V = √[2(P'/ρ)].................. Equation 1 ( From

Where V = Speed of the aircraft, Differential Pressure of the air craft, ρ = Density of air at an altitude of 3000 m.

Given: P' = 3100 N/m², ρ = 0.909 kg/m³

Substitute into equation 1

V = √[2(3100/0.909)]

V = √(2×3410.34)

V = √(6820.68)

V = 82.59 m/s

V = 297.324 km/h

Hence the speed of the aircraft is 82.59 m/s or 297.324 km/h

3 0

3 years ago

One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867

Thepotemich [5.8K]

<u>Answer:</u>

(A)

Density = Mass / Volume

Mass = Density × Volume

$= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene$

$1C_6 H_5 CH_3 + 9 O_2 > 7 CO_2 + 4 H_2 O$

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of $CO_2$ gas and 4 moles of $H_2 O$ Vapour

So the mole ratio is 1 : 11

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $$

(C)

1mole contains $6.022\times10^{23}$ molecules

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $$

6 0

3 years ago

Which of these boxes will not accelerate?

love history [14]

Answer:

B as all the forces cancel out

Explanation:

20-20=0

25-25=0

3 0

2 years ago

Calculate the heat energy released when 21.1 g of liquid mercury at 25.00 °C is converted to solid mercury at its melting point.

PSYCHO15rus [73]

Heat capacity yea urjjrjrjrbdnsnnend

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3 years ago