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disa [49]
3 years ago
13

What happens in terms of energy when a moving car hits a parked car, causing the parked car to move?

Physics
2 answers:
MrMuchimi3 years ago
8 0

<u>Answer;</u>

<em>The moving car transfers kinetic energy to the parked car. </em>

<u>Explanation;</u>

  • Energy is the ability of work to be done. It is measured in joules. The energy in an object depends on whether an object is in motion or at rest.
  • Kinetic energy is the energy possessed by a body in motion. Calculated by 1/2mv², where m is the mass of the body and v is the velocity of the body in motion. Therefore, the moving car possess kinetic energy.
  • When a body is at rest it posses potential energy. Thus, the parked car possessed kinetic energy which changed when it was hit by the moving car as the kinetic energy of the moving car was transferred to the parked car.

pickupchik [31]3 years ago
4 0

Answer:

<u>Option A. What happens in terms of energy when a moving car hits a parked car, causing the parked car to move, is that the moving car transfers kinetic energy to the parked car.</u>

Explanation:

Kinetic energy is energy in motion, objects that are moving all have kinetic energy. The more the object that is moving weights, and the faster that it moves, the more kinetic energy it will have. When a moving car hit a parked car, the moving car is transferring part of its kinetic energy to the parked car, that up to that moment had no energy at all, this transfer of energy from the moving car to the parked car will most likely make the parked car to move. The faster the moving car was moving before hitting the parked car, the further the parked car will move.

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A rabbit is moving in the positive x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 10.9 m/s al
anzhelika [568]

Answer:

aₓ = 0 ,       ay = -6.8125 m / s²

Explanation:

This is an exercise that we can solve with kinematics equations.

Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.

x axis

          vₓ = v₀ₓ = 1.10 m / s

          aₓ = 0

y axis

initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration

         v_{y}= v_{oy} -ay t

          ay = (v_{oy} -v_{y}) / t

          ay = (0 -10.9) / 1.6

          ay = -6.8125 m / s²

the sign indicates that the acceleration goes in the negative direction of the y axis

8 0
3 years ago
You have two square metal plates with side lengths of (6.50 C) cm. You want to make a parallel-plate capacitor that will hold a
gtnhenbr [62]

Answer:

The necessary separation between  the two parallel plates is 0.104 mm

Explanation:

Given;

length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}

Where;

d is the separation or distance between the two parallel plates;

d = \frac{VL^2 \epsilon_o}{Q} \\\\d =  \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm

Therefore, the necessary separation between  the two parallel plates is 0.104 mm

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Which tool would you use to measure the amount of rainfall?
zheka24 [161]

Answer:

a

Explanation:

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3 years ago
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What property of light shown in the picture?
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Answer:

Explanation:

Reflection

8 0
3 years ago
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THE RELATIVE ANGLE AT THE KNEE CHANGES FROM 0O TO 85O DURING THE KNEE FLEXION PHASE OF A SQUAT EXERCISE. IF 10 COMPLETE SQUATS A
Mice21 [21]

Answer: angular distance = 1700° and 29.7 rad

      also the angular displacement = 0

Explanation:

To explain this, i will give a breakdown of this works.

we are asked to find both the angular distance and displacement the knee undergo.

Ok to get the distance of the knee, we would first take note that for one to squat down and get back up, the knee would travel through 85° of flexion to gpo down, and also through another 85° of extension to return standing (upright). So, the actual angular distance of the squat is 170°.

taking ten squats, the knee would have to go through 170° motion times 10 i.e;

10 * 170° = 1700°

Therefore the angulaar distance is 1700°

now converting this distance to radians since we will be required to have our answer in both degree and rad.

Given that 2pi = 360°, it means that one degree will give 57.3°;

∅ (rad) = ∅ (deg) * 2π/360°

∅ (rad) = 1170° * 2π/360°  = 29.7 rad

∅ (rad) = 29.7 rad

b. For the other part, let us remember that angular displacement is equal to angular distance divided by time, so the angular displacement displacement of the knee will be zero, because the knee's position at the final third will be the same as the initial position.

cheers i hope this helps!!!!

π

5 0
3 years ago
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