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disa [49]
2 years ago
13

What happens in terms of energy when a moving car hits a parked car, causing the parked car to move?

Physics
2 answers:
MrMuchimi2 years ago
8 0

<u>Answer;</u>

<em>The moving car transfers kinetic energy to the parked car. </em>

<u>Explanation;</u>

  • Energy is the ability of work to be done. It is measured in joules. The energy in an object depends on whether an object is in motion or at rest.
  • Kinetic energy is the energy possessed by a body in motion. Calculated by 1/2mv², where m is the mass of the body and v is the velocity of the body in motion. Therefore, the moving car possess kinetic energy.
  • When a body is at rest it posses potential energy. Thus, the parked car possessed kinetic energy which changed when it was hit by the moving car as the kinetic energy of the moving car was transferred to the parked car.

pickupchik [31]2 years ago
4 0

Answer:

<u>Option A. What happens in terms of energy when a moving car hits a parked car, causing the parked car to move, is that the moving car transfers kinetic energy to the parked car.</u>

Explanation:

Kinetic energy is energy in motion, objects that are moving all have kinetic energy. The more the object that is moving weights, and the faster that it moves, the more kinetic energy it will have. When a moving car hit a parked car, the moving car is transferring part of its kinetic energy to the parked car, that up to that moment had no energy at all, this transfer of energy from the moving car to the parked car will most likely make the parked car to move. The faster the moving car was moving before hitting the parked car, the further the parked car will move.

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I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
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Ronch [10]

Answer:

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Explanation:

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f = \frac{Gm_{1}m_{2} }{d^{2} }

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4 0
2 years ago
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3 0
3 years ago
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Answer:

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Explanation:

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4 0
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