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Rudik [331]
3 years ago
11

One astronomer believes that the density of the universe remains constant. One physicist believes that the density of the univer

se changes over a period of time. Which of these statements best explains why the astronomer and physicist have different views on the density of the universe? Most data on density of the universe are inaccurate. Scientists provide different theories to strengthen science. Scientists having different interests arrive at different conclusions. Most experiments on density of the universe cannot be repeated.
Physics
1 answer:
Alja [10]3 years ago
4 0
The correct option is this: SCIENTISTS HAVING DIFFERENT INTERESTS ARRIVE AT DIFFERENT CONCLUSIONS.
There are many fields in science and the scientists working in these fields have varying interests. The interests that a scientist has in a certain research will determines his views and conclusions about such a research.<span />
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We know that religion was important to healthcare practices in ancient Egypt the best support this is
Nonamiya [84]
Assuming there are no choices, the answer might be the practice of calling upon gods and goddesses to help the sick.
7 0
3 years ago
According to the Newton’s first law of motion , which of the following objects will change in motion
Kobotan [32]
The correct answer is C
4 0
3 years ago
Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human
kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

\Delta t = \Delta t' * \sqrt{1 - x^2}

\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}

1 - x^2 = (\frac{\Delta t}{\Delta t'})^2

x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2

x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}

x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986

It would need to travel at 0.9999986*c

5 0
3 years ago
2. A compression at a constant pressure of 20 kPa is performed on 9.0 moles of an ideal monatomic gas (Cv-1.5R). The compression
Fofino [41]

Answer:

- 4.2 kJ

Explanation:

We shall find out the initial temperature of the gas

PV / T = n R

20 X 10³ X .26 / T = 9 X 8.3

T = 69.6 K

Since the pressure of gas is constant

V / T = constant

V₁ / T₁ = V₂ / T₂

.26 / 69.6 = .12 / T₂

T₂ = 32.12 K

gas is cooling so there will be decrease in internal energy

Change in temperature = 69.6 - 32.12

= 37.48 K.

decrease in internal energy

= - n Cv x fall in temperature

= - 9 x 1.5 x 8.31 x 37.48  ( Cv = 1.5 R given )

= - 4.2 kJ .

8 0
3 years ago
A hydrogen atom consists of a proton and an electron. If the orbital radius of the electron increases
tamaranim1 [39]

Answer:

The potential energy increases  if the orbital radius increases.

Explanation:

  The orbital radius of the electron increases means the distance from the nucleus of the hydrogen atom increase.

 The nucleus is positively charged .

The potential energy is given by  P.E = -\frac{Ze^{2} }{r}

             where Z is the atomic number      

                           r is the radius

The negative sign indicates that the electron which is revolving is bound to nucleus.

As the radius and potential energy are inversely proportional it is clear that when <em>radius increase</em> the<em> potential energy become less negative </em>which means the potential energy increases when the orbital radius increase.

5 0
3 years ago
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