Question

Prove that? sec^2a-1-tan^2a=0​

Answer 1

Answer:

You have to apply Basic Trigonometric Identities :

${sec}^{2} (θ) = {tan}^{2} (θ)+ 1$

So for this question :

${sec}^{2} (a) - 1 - {tan}^{2} (a) = 0$

$LHS = {sec}^{2} (a) - 1 - {tan}^{2}(a)$

$LHS = {tan}^{2} (a) + 1 - 1 - {tan}^{2} (a)$

$LHS = 0$

$LHS = RHS \: (proven)$