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2 years ago

How can I find the three iterations of 3^(x)= 2^(-x)+4

Mathematics

1 answer:

DIA [1.3K]2 years ago

5 0

After factorizing the given equation, we can find the three iterations by putting the consecutive values of x.

The given equation is 3∧x = 2∧(-x) + 4. We can modify it as shown below:

Take logarithm on both the sides

log(3∧x) = log[2∧(-x) + 4]

xlog3 = log[2∧(-x) + 4]

x = log[2∧(-x) + 4] / log3

For the first iteration, put x = 1

x = log[2∧(-1) + 4] / log3

x = log4.5 / log3

x = 0.477

For the second iteration, put x = 2

x = log[2∧(-2) + 4] / log3

x = log4.25 / log3

x = 0.477

For the third iteration, put x = 3

x = log[2∧(-3) + 4] / log3

x = log4.125 / log3

x = 0.477

So, this is how we can find three iterations.

For more explanation about iterations, refer the following link:

brainly.com/question/14828536

#SPJ10

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The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

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Reason:

The slope and intercept form is the form y = m·x + c

Where;

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Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

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Slope, m₂ = $\dfrac{1}{2}$

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$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

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