Answer: 178.25*10^-6 T
Explanation: In order to solve this problem we have to take into account the equilibrium between the electric and magnetic forces in the electron, so it is given by:
Fm=evB
Fe=eE so
evB=eE the we have
v=E/B
Firsly we calculate the velocity of the electron before to get the parallel plates at 100V
eΔV=1/2*m*v^2 then
v=(2*eΔV/m)^1/2
v=(2*1.6*10^-19*3.1*10^3/9.1*10^-31)^1/2=33 *10^6 m/s
Then we can calculate B
B=E/v E.d=V where d is the separation between the plates and V is equal a 100V
B=V/(d*v)=100/(17*10^-3*33 *10^6)=178.25*10^-6 T
I think the correct answer is going to be A
Answer:
The ratio of electric force to the gravitational force is 
Explanation:
It is given that,
Distance between electron and proton, 
Electric force is given by :

Gravitational force is given by :

Where
is mass of electron, 
is mass of proton, 
is charge on electron, 
is charge on proton, 



So, the ratio of electric force to the gravitational force is
. Hence, this is the required solution.
-- Put the rod into the freezer for a while. As it cools,
it contracts (gets smaller) slightly.
-- Put the cylinder into hot hot water for a while. As it heats,
it expands (gets bigger) slightly.
-- Bring the rod and the cylinder togther quickly, before the
rod has a chance to warm up or the cylinder has a chance
to cool off.
-- I bet it'll fit now.
-- But be careful . . . get the rod exactly where you want it as fast
as you can. Once both pieces come back to the same temperature,
and the rod expands a little and the cylinder contracts a little, the fit
will be so tight that you'll probably never get them apart again, or even
move the rod.
Answer:
More force
Explanation:
Object A has more mass than object B
For object A to accelerate at the same rate as object B, it will need more force.
According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".
Net force = mass x acceleration
Now, if a body has more mass and needs to accelerate at the same rate as another one with a lower mass, the force on it must be increased.