Question

Write a Lewis structure for OF2, then answer the following questions about the Lewis structure. 1. How many valence electrons does this compound have? 2. How many bonded electrons does this compound have? 3. How many lone pairs of electrons does this compound have? 4. How many single bonds does this compound have?

Answer 1

Answer :

(1) The number of valence electrons present in the compound is, 20

(2) The number of bonded electrons present in the compound is, 4

(3) The number of lone pair electrons present in the compound is, 16

(4) The number of single bonds present in the compound is, 2

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $OF_2$

As we know that oxygen has '6' valence electrons and fluorine has '7' valence electrons.

Therefore, the total number of valence electrons in $OF_2$ = 6 + 2(7) = 20

According to Lewis-dot structure, there are 4 number of bonding electrons and 16 number of non-bonding electrons or lone pair of electrons.

The Lewis-dot structure of $OF_2$ is shown below.