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2 years ago

Don’t waste your time answering with links because I won’t even open it. Plz just give a normal answer. Thanks.

Chemistry

2 answers:

Norma-Jean [14]2 years ago

3 0

im really sorry I need points so I’m answering this again really sorry!

Alexeev081 [22]2 years ago

3 0

Answer:

Not sure if you still need help, but here ya go. I'm not going to rewrite the chemical names, so this is the order of answers.

P2H6

NO3

N4H6

Explanation:

Just gotta break down the names and look at the roots. I'll walk through the first one.

ex) Diphosphorus hexahydride:

Di means two, and Phosphorus means just that, phosphorus. So we have two phosphorus, represented by P on the periodic table. So, P2

Hexa means 6, and hydride means hydrogen. We know this because we take the part of the word before 'ide' to get hydr, the first part of hydrogen.

Thus, we have six hydrogen, represents by an H on the periodic table. So, H6

Put it together, we have P2H6

Just have to do that to all the other ones. Look at the prefix to get the number of atoms, then the suffix to know what the atom is. That being said, KNOW YOUR PREFIXES or this gets really hard.

note: metals, if compound is ionic, are always first in the name

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Answer:

a. pH = 2 b. pH = 3 c. pH = 1 d. Unanswerable

Explanation:

pH = -log[H+] OR pH = -log{H3O+]

and inversely

pOH = -log[OH-]

1. Determine what substance you are working with, (acid/base)

2. Determine whether or not that acid or base is strong or weak.

a. 1.0 x 10^-2M HCl

HCl is a strong acid, therefore it will dissociate completely into H+ and Cl- with all ions going to the H+, therefore, the concentration of HCl and concentration of H+ are going to be equal, meaning we simply take the negative logarithm of the concentration of HCl and that would equal pH

pH = -log[H+]

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b. 1.0 x 10^-3M HNO3

HNO3 like part a, is a strong acid, therefore it would simply require you to take the negative logarithm of the concentration of the compound itself, to find its pH.

pH = -log[H+]

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pH = 3

c. 1.0 x 10^-1M HI

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pH = 1

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