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3 years ago

Don’t waste your time answering with links because I won’t even open it. Plz just give a normal answer. Thanks.

Chemistry

2 answers:

Norma-Jean [14]3 years ago

3 0

im really sorry I need points so I’m answering this again really sorry!

Alexeev081 [22]3 years ago

3 0

Answer:

Not sure if you still need help, but here ya go. I'm not going to rewrite the chemical names, so this is the order of answers.

P2H6

NO3

N4H6

Explanation:

Just gotta break down the names and look at the roots. I'll walk through the first one.

ex) Diphosphorus hexahydride:

Di means two, and Phosphorus means just that, phosphorus. So we have two phosphorus, represented by P on the periodic table. So, P2

Hexa means 6, and hydride means hydrogen. We know this because we take the part of the word before 'ide' to get hydr, the first part of hydrogen.

Thus, we have six hydrogen, represents by an H on the periodic table. So, H6

Put it together, we have P2H6

Just have to do that to all the other ones. Look at the prefix to get the number of atoms, then the suffix to know what the atom is. That being said, KNOW YOUR PREFIXES or this gets really hard.

note: metals, if compound is ionic, are always first in the name

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3 years ago

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3 years ago

Which option is an example of a physical property?

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4 years ago

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At 25°C and constant pressure, carbon monoxide gas combines with oxygen gas to give carbon dioxide gas with the evolution of 10.

stealth61 [152]

Answer : The value of $\Delta H$ for the reaction is, -565.6 kJ

Explanation :

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Molar mass CO = Atomic mass of C + Atomic mass of O = 12 + 16 = 28 g/mole

Now we have to calculate the moles of CO.

$\text{Moles of }CO=\frac{\text{Mass of }CO}{\text{Molar mass of }CO}=\frac{1g}{28g/mole}=\frac{1}{28}mole$

Now we have to calculate the value of $\Delta H$ for the reaction.

The balanced equation will be,

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

From the balanced chemical reaction we conclude that,

As, $\frac{1}{28}mole$ of CO release heat = 10.1 kJ

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3 years ago

Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g

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The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

The reaction for the decomposition of water has been:

$\rm 2\;H_2O\;\rightarrow\;H_2\;+\;O_2$

From the balanced equation, 2 moles of water decomposes to form 1 moles of hydrogen and 1 mole of oxygen.

The mass of oxygen produced has been 50 g. The moles of oxygen has been given by:

$\rm Moles=\dfrac{mass}{molar\;mass}$

The moles of oxygen has been:

$\rm Moles_O_2=\dfrac{50}{32}\;mol\\Moles_O_2=1.5625\;mol$

The moles of oxygen produced has been 1.5625 mol.

The moles of hydrogen decomposed has been given from the balanced chemical equation as:

$\rm 1 \;mole\;O_2=2\;mole\;H_2O\\1.5625\;mol\;O_2=1.5625\;\times\;2\;mol\;H_2O\\1.5625\;mol\;O_2=3.125\;mol\;H_2O$

The moles of hydrogen decomposes has been 3.125 mol.

The mass of hydrogen decomposed has been given by:

$\rm Mass=moles\;times\;molar\;mass\\Mass_{H_2O}=3.125\;\times\;18.01\;g\\Mass_{H_2O}=56.28\;g$

The mass of water decomposed to produce 50 g oxygen has been 56.28 g. Thus, option D is correct.

For more information about moles produced, refer to the link:

brainly.com/question/10606802

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2 years ago