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LenKa [72]
3 years ago
13

A particular 3.0 L solution contains 2.5 mmol (millimoles) of a substance. What is the concentration of this solution in number

of molecules per cubic meter? g
Chemistry
1 answer:
bearhunter [10]3 years ago
8 0

Answer: 0.83mol/m3

Explanation:

Number of mole = 2.5 mmol = 0.0025mol

Recall

1L = 0.001m3

Therefore 3L = 3x0.001 = 0.003m3

0.003m3 contains 0.0025mol

Therefore, 1m3 will contain = 0.0025/0.003 = 0.83mol

The concentration in mol/m3 is 0.83mol/m3

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The burning of propane gas can be represented as a balanced chemical reaction as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calcula
Snezhnost [94]

Answer: 20L of H2O

Explanation:

C3H8 + 5O2 → 3CO2 + 4H2O

Recall 1mole of a gas contains 22.4L at stp

5moles of O2 contains = 5 x 22.4 = 112L

4moles of H2O contains = 4 x 22.4 = 89.6L

From the equation,

112L of O2 produced 89.6L H2O

There for 25L of O2 will produce XL of H2O i.e

XL of H2O = (25 x 89.6)/112 = 20L

6 0
3 years ago
Which describes the elements in a given group of the periodic table?
victus00 [196]
C is the answer I think
3 0
3 years ago
Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
3 years ago
Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
4 years ago
Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1
masha68 [24]

Answer:

The pH of the solution will be 7.53.

Explanation:

Dissociation constant of KClO=K_a=2.8\times 10^{-8}

Concentration of acid in 1 l= 0.30 M

Then in 200 ml = 0.30 M\times 0.200 L=0.06 M

The concentration of acid, HClO=[acid]= 0.006 M

Concentration of salt in 1 L = 0.20 M

Then in 300 ml = 0.20 M\times 0.300 L=0.06 M

The concentration of acid, KClO=[salt]= 0.006 M

The pH of the solution will be given by formula :

pH=pK_{a}^o+\log\frac{[salt]}{[acid]}

pH=-\log[2.8\times 10^{-8}]+\frac{[0.06 M]}{[0.06 M]}

The pH of the solution will be 7.53.

4 0
3 years ago
Read 2 more answers
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