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AfilCa [17]
3 years ago
5

Is the following nuclear equation balanced? 214 82pb 4 2He 210 80 yes or no​

Chemistry
1 answer:
Verizon [17]3 years ago
8 0

Answer:

no

Explanation:

I think it is no because I like the word no it has a very nice ring to it and it is fun to say I say it a lot and it is just very very fun that is my brilliant explanation for you . goodbye.

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How many atoms of potassium are in 0.250 mol of potassium carbonate, k2co3?
Verizon [17]
The  number  of  potassium  atom  that  are  in  0.25  moles   potassium  carbonate  is  calculated  as  follows

by  use  of Avogadro  contant

1  mole=  6.02  x10^23   atoms

what  about  0.25 moles,   
by  close  multiplication

{0.250 moles  x 6.02  x10^23}  /  1 mole  =  1.505  x10^23  atoms
4 0
3 years ago
How many moles of Boron (B) are in 5.03 x 1024 B atoms?
goldfiish [28.3K]

Hey there!:

Number of moles =   ( number of atoms / 6.023*10²³ atoms )

given number of atoms = 5.03*10²⁴

Therefore:

Number of moles B = 5.03*10²⁴ / 6.023*10²³

Number of moles B = 8.35 moles

Hope that helps!


3 0
3 years ago
Calculate the no. of each atoms presents in 10 grams of calcium carbonate.
raketka [301]

Molar Mass of Calcium carbonate:-

\\ \sf\longmapsto CaCO_3

\\ \sf\longmapsto 40u+12u+3(16u)

\\ \sf\longmapsto 52u+48u

\\ \sf\longmapsto 100u

\\ \sf\longmapsto 100g/mol

  • Given Mass=10g

\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \sf\longmapsto No\:of\;moles=\dfrac{10}{100}

\\ \sf\longmapsto No\:of\:moles=0.1mol

Now

\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}

\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{22}molecules

8 0
3 years ago
3 Apply Use context clues to write your own definitions for the words definite and occupy.
motikmotik

Answer:

Explanation:

own definitions for the words definite and occupy.

Example sentence

Solid is the state of matter that has a definite shape and volume.

definite:

__________

Example sentence

A larger container will allow a gas to occupy more space.

occupy:

3 0
2 years ago
The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D
dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

                                             = 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free   energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so,  0 = ΔH - T (Δ S)

      T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

6 0
3 years ago
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