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3 years ago

Systems of the Body Constructed Response

Mathematics

1 answer:

fiasKO [112]3 years ago

6 0

Answer:

note: there may be other possible explanations and more body systems can be involved and I can go into much greater detail

1: Nervous system signals your muscles in mouth to abduct and adduct as well as your salivary glands to produce saliva to break down the food, as well as prepare the stomach to digest the food

2: Muscular system moves muscles in mouth to break food down into smaller pieces so there is greater surface area for digestive enzymes to work on the food, then muscles in oesophagus move food to stomach, where stomach muscles churn the broken down food around to speed up digestion

3: Digestive system releases numerous digestive enzymes into the food to break down lipids, carbohydrates and proteins. Small intestines absorb nutrients into bloodstream, and large intestine absorbs water.

4: Excretory system removes excess mostly dry waste through the anus as well as urine from ureter.

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30 less than 10 mean

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4 years ago

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4 years ago

Suppose 45% of the population has a college degree.

levacccp [35]

Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

The proportion estimate and the sample size are given as follows:

p = 0.45, n = 437.

Hence the mean and the standard error are:

$\mu = p = 0.45$

$s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.45(0.55)}{437}} = 0.0238$

The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.

Hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

Z = (0.42 - 0.45)/0.0238

Z = -1.26

Z = -1.26 has a p-value of 0.1038.

2 x 0.1038 = 0.2076.

0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

More can be learned about the normal distribution at brainly.com/question/28159597

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2 years ago

How many solutions does this system of equations have? y = 3x + 4 y = 3x – 1

Darina [25.2K]

I think the answer is 4y=-1 y=-1/4

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4 years ago

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