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3 years ago

Please help I don’t understand

Mathematics

1 answer:

marta [7]3 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

The 2 strokes through XM and MY indicate the segments are congruent, so

YM = MX , that is

8x - 24 = 3x + 1 ( subtract 3x from both sides )

5x - 24 = 1 ( add 24 to both sides )

5x = 25 ( divide both sides by 5 )

x = 5

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Find the zeros of f(x) = x^2+5x-6.<br> A. {-2,3}<br> B. {-6,1}<br> c. {-2,-3}<br> D. {-6,-1}

Arisa [49]

Answer:

x^2+5x-6

a = 1 b = 5 and c = -6

Using the quadratic formula:

x = [-5 +- sq root (25 -4 * 1 *-6) ] / 2 * 1

x = [-5 +- sq root (49)] / 2

x = [-5 +- 7] / 2

x1 = 1

x2 = -6

Step-by-step explanation:

7 0

3 years ago

rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a

SpyIntel [72]

Answer:

The point O can be (x,y) or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.

7 0

3 years ago

Guys can you please help me I really dont understand algebra?

KonstantinChe [14]

Yes it is linear since it's in the standard form Ax+By = C

A = 2

B = -8

C = 16

6 0

2 years ago

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1/360
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3 years ago

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Find the missing b for a trapezoid with a=68, h=4, b=21

MAVERICK [17]

We will have to use the formula for the area of a trapezoid on this problem, which is ( $b_1$ and $b_2$ are the bases of the trapezoid and $h$ is the height):

$\dfrac{b_1 + b_2}{2} \cdot h$

All we need to do is substitute the information we are given into our formula:

$\dfrac{21 + b_2}{2} \cdot 4 = 68$

Now, let's just simplify the equation:

$\dfrac{21 + b_2}{2} \cdot 4 = 68$

$\dfrac{21 + b_2}{2} = 17$

$21 + b_2 = 34$

$b_2 = 13$

The missing base has a length of 13 units.

4 0

3 years ago