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Annette [7]
3 years ago
7

What is the completely factored form of f(x)=x^3+4x^2+7x+6?

Mathematics
1 answer:
Reptile [31]3 years ago
7 0

we are given

f(x)=x^3+4x^2+7x+6

We will use rational root theorem to find factors

We can see that

Leading coefficient =1

constant term is 6

so, we will find all possible factors of 6

6=\pm 1,\pm 2,\pm 3,\pm 6

now, we will check each terms

At x=-2:

We can use synthetic division

we get

f(-2)=0

so, x+2 will be factor

and we can write our expression from synthetic division as

f(x)=x^3+4x^2+7x+6=(x+2)(x^2+2x+3)

f(x)=(x+2)(x^2+2x+3)

now, we can find factor of remaining terms

x^2+2x+3=0

we can use quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

we can compare our equation with quadratic equation

we get

a=1,b=2,c=3

now, we can plug these values

x=\frac{-2+\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}

x=-1+\sqrt{2}i

x=\frac{-2-\sqrt{2^2-4\cdot \:1\cdot \:3}}{2\cdot \:1}

x=-1-\sqrt{2}i

so, we get

x=-1+\sqrt{2}i,\:x=-1-\sqrt{2}i

so, we can write factor as

x^2+2x+3=(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))

so, we get completely factored form as

f(x)=(x+2)(x-(-1+\sqrt{2}i))(x-(-1-\sqrt{2}i))...............Answer


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