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pochemuha
4 years ago
6

Change 0.00765 kL into mL

Chemistry
2 answers:
bagirrra123 [75]4 years ago
4 0

Answer:

7650

Explanation:

formula- multiply the volume value by 1e+6

kvasek [131]4 years ago
3 0

Answer

7650

multiply the volume value by 1+6

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A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in
kati45 [8]

Answer:

<h2>22.366 kPa</h2>

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

58.6 kPa = 58600 Pa

We have

P_2 =  \frac{58600 \times 250}{655}  =  \frac{14650000}{655}  \\  = 22366.4122... \\  = 22366

We have the final answer as

<h3>22.366 kPa</h3>

Hope this helps you

3 0
3 years ago
Question 10 of 23
Margarita [4]

Answer: O D. A digital signal moves between a discrete number of values.

Explanation:

The digital signals are considered more reliable over the analog signals as they encode the information in a coded form. The bits or samples of the data are transmitted and converted into digital and numerical value. The stream of encoded data is in the form of continuous data at regular time intervals. It provides information in waveform and the data is in compact form. The data is in the form of binary bits 0 and 1 so greater the number of bits greater will be the greater will be the resolution of the information.

7 0
3 years ago
which of the following has to remain constant to allow you to use the combine gas law for calculations?​
kap26 [50]

Answer:

The amount of gas is what I came up with

5 0
4 years ago
When coal goes through combustion it releases nitrogen and sulpur into the air in the form of what
katen-ka-za [31]

Answer:

Over time, the plant matter transforms from moist, low-carbon peat, to coal, All types of coal also contain sulfur, which, when burned, releases toxic air pollution. Sulfur All this coal comes from mines, which are either underground or run on diesel—a major source of air toxins, nitrogen oxide, and soot.

7 0
3 years ago
A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
AysviL [449]

Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.

the equation we use is, q=mc\Delta T .

where, q is the heat energy, m is mass, c is specific heat and \Delta T is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is \frac{1.035cal}{g.^0C} .

\Delta T  for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

\Delta T  for metal = 11.08 - 45.00 = -33.92 degree C

let's plug in the values in the above equation and calculate heat gained by combined system.

q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C

q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.


3 0
4 years ago
Read 2 more answers
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