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A. The balanced chemical reaction of Sodium metal and Water is 2Na + 2H₂O → 2NaOH + H₂.
<h3>What is a balanced chemical equation? </h3>
A balanced equation contains the same number of each type of atoms on both the left and right sides of the reaction arrow.
<h3>Reaction of Sodium metal and Water</h3>
Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2).
The balanced chemical reaction is written below;
2Na + 2H₂O → 2NaOH + H₂
Thus, the balanced chemical reaction of Sodium metal and Water is 2Na + 2H₂O → 2NaOH + H₂.
Learn more about chemical reaction here: brainly.com/question/11231920
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Answer:
146 g
Explanation:
Step 1. Calculate the <em>molar mass</em> of NaNO₃
Na = 22.99
N = 14.01
3O = 3 × 16.00 = 48.00
Total = 85.00 g/mol
Step 2. Calculate the <em>mass</em> of NaNO₃
Mass of NaNO₃ = 1.72 × 85.00/1
Mass of NaNO₃ = 146 g
If anything you would use a protractor but that’s not a answer.... so I would pick whatever relates to a protractor
Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Explanation:
- Firstly, we need to identify the reducing agent and the oxidizing agent.
- The reducing agent: is the agent that has been oxidized via losing electrons.
- The oxidizing agent: is the agent that has been reduced via gaining electrons.
- Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.
- So, Ti is the reducing agent because its oxidation state changes from 0 to +4.
- Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
- Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.