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Bogdan [553]
3 years ago
5

What is the largest body in our solar system

Chemistry
2 answers:
patriot [66]3 years ago
7 0
The Largest. There are 17 bodies in the solar system whose radius is greater than 1000 km. The composite above shows the Sun and the 5 largest planets at a scale of 3200 km/pixel. (Earth<span> is the tiny spot between Jupiter and the Sun) so the sun is the largest body in our solar system. hope this helped! ^^</span>
Ostrovityanka [42]3 years ago
4 0
The sun is the largest body in our solar system


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Explain how mass and energy can be conserved even during a chemical change.
AleksandrR [38]
Mass/ energy can not be created or destroyed 
4 0
3 years ago
29. What is the noble gas configuration for tellurium?
Whitepunk [10]

Answer:

[Kr] 4d10 5s2 5p4 is the electronic configuration for tellurium.

Electrons per shell: 2,8,18,18,6

Atomic number: 52

Symbol: Te

5 0
3 years ago
What did Democritus call small, indivisible particles that make up?​
Fynjy0 [20]

Answer:

atomos

Explanation:

2,500 years ago, Democritus suggested that all matter in the universe was made up of tiny, indivisible, solid objects he called "atomos." However, other Greek philosophers disliked Democritus' "atomos" theory because they felt it was illogical.

8 0
2 years ago
Cuál es el radio atómico de una molécula diatómica si su diámetro es de 2,28 angstroms?
aliya0001 [1]

Answer:

1.14 angstroms

Explanation:

Matemáticamente, el radio atómico de una molécula diatómica se define como la mitad del diámetro de la molécula diatómica.

Esto significa que para obtener el valor del radio atómico de la molécula diatómica, necesitamos dividir el diámetro de la molécula diatómica entre 2 En esta pregunta, lo que haremos es dividir el diámetro dado en la pregunta por 2 Por lo tanto,

el radio atómico será 2.28 angstroms / 2 = 1.14 angstroms Entonces, el radio atómico de la molécula diatómica es 1.14 angstroms

7 0
3 years ago
A stream of hot wat at 85 deg C at a rate of 1 kg/s is needed for the pasteurizing unit in a milk bottling plant. Such a stream
charle [14.2K]

Answer:

the flow rate for steam from the boiler plant = 0.099kg/s

the flow rate from the city water = 0.901 kg/s

the rate of entropy production in the mixing tank = 0.2044 kJ/k

Explanation:

In a well-insulated mixing tank where:

Q_{cv} = 0  & W_{cv}=0

The mass flow rates can be calculated using the formula:

Q_cv+m_1h_1+m_2h_2=m_3h_3+W_{cv      ------ equation (1)

so;

0+m_1h_1+m_2h_2=m_3h_3+0               ------- equation (2)

Given that:

From the steam in the boiler plant;

The temperature (T₁) = 200°C

Pressure (P₁) = 10 bar

The following data from compressed water and super-heated steam tables were also obtained at: T₁ = 200°C

h₁ = 2828.27 kJ/kg

s₁ = 6.95 kJ/kg K

m₁ (flow rate for steam in the boiler plant) = ????

Also, for city water

The temperature (T₂) = 20°C

Pressure (P₂) = 1 bar

Data obtained from compressed water and super-heated steam tables are as follows:

h₂ = 84.01 kJ/kg

s₂ = 0.2965 kJ/kg K

m₂ (flow rate for city water) = ???

For  stream of hot wat at 85 deg C

Temperature (T₃) = 85°C

h₃(h_f) = 355.95 kJ/kg

s₃(s_f) = 1.1344 kJ/kg K

m₃ = 1 kg/s

so since:

m₁ + m₂ = m₃       (since m₃  = 1)

m₂ = 1 -  m₁

From equation (2);

0+m_1h_1+m_2h_2=m_3h_3+0    

= m_1(2828.27)+(1-m_1)(84.01)=1(355.95)

= 2828.27m_1+(84.01-84.01m_1)=(355.95)

= 2828.27m_1-84.01m_1=355.95-84.01

= m_1(2828.27-84.01)=355.95-84.01

m_1 =  \frac{355.95-84.01}{2828.27-84.01}

m_1 =  \frac{271.94}{2744.26}m_1 =  0.099 kg/s

∴ the flow rate for steam from the boiler plant = 0.099kg/s

since; m₂ = 1 -  m₁

m₂ = 1 -  0.099 kg/s

m₂ = 0.901 kg/s

∴ the flow rate from the city water = 0.901 kg/s

b)

rate of entropy production in the mixing tank can be determined using the formula:

ΔS_{production} = m_3}s_3-(m_1s_1+m_2s_2)

ΔS_{production} = (1)(1.1344)-(0.099)(6.6955)-0.901(0.2965)

ΔS_{production} = 1.1344-0.6628545-0.2671465

ΔS_{production} = 1.1344 - 0.930001

ΔS_{production} = 0.204399

ΔS_{production} ≅ 0.2044 kJ/k

∴ the rate of entropy production in the mixing tank = 0.2044 kJ/k

6 0
3 years ago
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