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IRISSAK [1]
3 years ago
12

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 4.10 kg of water at 37.5 degre

e C. During the reaction 125. kJ of heat flows out of the flask and into the bath.
Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18 J middot g^-1middot K^-1. Round your answer to 3 significant digits.
Chemistry
1 answer:
sveta [45]3 years ago
8 0

Answer:

44.7 degree (3 s.f)

Explanation:

mass of water = 4.10Kg

Initial temperature = 37.5C

Final temperature = x

Heat = 125 kJ = 125000 J

Specific heat capacity = 4180 J/kg°C

These parameters are given by:

H = MCΔT

ΔT = H / MC

ΔT = 125000 / (4.10 * 4180)

ΔT = 7.294

ΔT = T2 - T1

T2 = ΔT + T1

T2 = 7.294 + 37.5

T2 = 44.794 = 44.7 degree (3 s.f)

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4 years ago
For the reaction, a → b, the rate constant is 0.0208 m-1 sec-1. How long would it take for [a] to decrease from 0.100 to 0.0450
goldfiish [28.3K]

First, assume the order of the given reaction is n, then the rate of reaction i.e. \frac{dx}{dt}=k\times[A]^{n}

where, dx is change in concentration of A in small time interval dt and k is rate constant.

According to units of rate constant, the reaction is of second order.

\frac{1}{[A]_{t}}-\frac{1}{[A]_{o}} = kt   (second order formula)

Put the values,

\frac{1}{0.04590 m}-\frac{1}{0.100 m} =0.0208 m^{-1}s^{-1} \times t  

 22.23 m -10 m =0.0208 m^{-1}s^{-1} \times t

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5 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:
uysha [10]

Answer:

The wavelength of the line in the absorption line spectrum of hydrogen caused by transition is 657.1 nm.

Explanation:

Energy of the electron in a hydrogen atom in nth shell:

E=\frac{-R_y}{n^2}

R_y=2.178\times 10^{-18} J

Energy of an electron in n = 2:

E_2=\frac{-R_y}{2^2}=-\frac{R_y}{4}

Energy of an electron in n = 3:

E_3=\frac{-R_y}{3^2}=-\frac{R_y}{9}

Energy difference in between both the shells:

\Delta E=E_3-E_2 :

=-\frac{R_y}{9}-(-\frac{R_y}{4})=\frac{5R_y}{36}

\Delta E=\frac{5R_y}{36} =\frac{5\times 2.178\times 10^{-18} J}{36}

=3.025\times 10^{-19} J

\Delta E=3.025\times 10^{-19} J=\frac{hc}{\lambda}

\lambda =\frac{hc\times 36}{3.025\times 10^{-19} J}

=\frac{6.626\times 10^{-34} J s\times 3\times 10^8 m/s}{3.025\times 10^{-19} J}

\lambda =6.571\times 10^{-7} m=657.1 nm

1 m = 10^9 nm

The wavelength of the line in the absorption line spectrum of hydrogen caused by transition is 657.1 nm.

8 0
4 years ago
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