Answer:
1. The electronic configuration of X is: 1s2 2s2 sp6 3s2
2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
3. The formula of the compound form by X and Y is given as: XY
Explanation:
For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:
1s2 2s2 sp6 3s2
To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:
Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below
1s2 2s2 2p4
The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
The formula of the compound form by X and Y is given below :
X^2+ + Y^2- —> XY
Their valency will cancel out thus forming XY
Explanation:
What is true about an atom in an excited state? Select all that apply:
A. It is less likely to enter chemical reactions.
B. It is more likely to enter chemical reactions.
C. It has less energy than a ground state atom.
D. It has more energy than a ground state atom.
Answer:
Explanation:
Butane is an alkane and has no multiple bond in it.
The isomers of butane are
a) n-butane
b) t-butane
The structures are shown in the figure.
The most stable radical will be tertiary butyl radical.
The structures are shown in figure.
