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maw [93]
2 years ago
14

mass of 2 * 10^21 number of atoms of an element is 0.4g. what is the mass of 0.5 mole of the element?​

Chemistry
1 answer:
astraxan [27]2 years ago
8 0

The mass of 0.5 moles of the element : 60.241 g

<h3>Further explanation</h3>

Given

mass of 2 x 10²¹ number of atoms of an element is 0.4 g

Required

the mass of 0.5 mole

Solution

Find relative atomic mass of the element(Ar)

mol of 2 x 10²¹ atoms :

\tt n=\dfrac{N}{No}=\dfrac{2.10^{21}}{6.02.10^{23}}=3.32.10^{-3}

\tt Ar=\dfrac{mass}{mol}=\dfrac{0.4}{3.32.10^{-3}}=120.482

the mass of 0.5 moles :

\tt mass=mol\times Ar\\\\mass=0.5\times 120.482=60.241~g

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<em><u>Answer and Explanation:</u></em>

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<em><u>For % of N2 gas: </u></em>

<em><u /></em>100\% - (5\% + 12\%) = 83\% ~N2<em><u /></em>

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3 0
3 years ago
What is the empirical formula of a compound that is 41.4% Strontium, 13.24%
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6 0
2 years ago
A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts
Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

                    1 quarts = 0.95 liter

                   7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

        Given:

            1 liter of solution contains 61.2g of barium nitrate:

          7.125 liter will contain  7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

  In solution we have  Ba²⁺ + NO₃⁻

                Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

 

Number of moles of Ba(NO₃)₂ = \frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = \frac{436.05}{271} = 1.609mole

      1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

    therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions  x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0
3 years ago
What is produced when 50mLs of carbon and 30mLs of oxygen react
dsp73

50ml of carbon dioxide.

hope this helps

3 0
3 years ago
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