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3 years ago

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How much momentum does a 5 kg bowling ball have when its traveling at a velocity of 8 m/s? Question 6 options: 40 kg*m/s 0.625 k

g*m/s 3 kg*m/s 1.6 kg*m/s

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

The momentum of the bowling ball is 40 kg m/s.

Explanation:

Momentum is defined as the product of mass and velocity acting on that object. So it is a measure of the change in the velocity for the given force with the mass of the object.

Momentum = Mass × Velocity.

As the mass of the object is given as 5 kg and the velocity is given as 8 m/s, then the momentum will be

Momentum = 5 kg × 8 m/s = 40 kg m/s.

So, the momentum of the bowling ball is 40 kg m/s.

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Explain two scenarios where a large truck can have the same momentum as a small car.

KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

$p=mv\cdots(i)$

Let $M_L$ and $M_S$ be the masses of the large truck and the car respectively, and $V_L$ and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck $= M_LV_L$

and the momentum of the small car $= M_SV_S$ .

If the large truck has the same momentum as a small car, then the condition is

$M_LV_L=M_SV_S\cdots(ii)$

The equation (ii) can be rearranged as

$\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}$

So, the first scenario:

$\frac {M_L}{M_S}=\frac {V_S}{V_L}$

$\Rhghtarrow M_L:M_S=V_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

$\frac{M_L}{V_S}=\frac{M_S}{V_L}$

$\Rhghtarrow M_L:V_S= M_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0

3 years ago

If a car is traveling 100 km/h west and comes to a stop in 3 min, what is the car's acceleration? Need procedure.

zmey [24]

Answer:

a = 0.154 [m/s^2]

Explanation:

To solve this problem we must use the following formula of kinematics.

$v_{f}= v_{i}-(a*t)\\$

where:

Vf = final velocity = 0

Vi = initial velocity = 100 [km/h]

t = time = 3 [min] = 180 [s]

Now we need to convert the velocity from [km/h] to [m/s]

$100[\frac{km}{h} ]*1000[\frac{m}{1km} ]*1[\frac{h}{3600s} ]=27.77[\frac{m}{s} ]$

0 = 27.77 - (a*180)

a = 0.154 [m/s^2]

Note: the negative sign of the equation shows, that the car slows down until it stops

6 0

3 years ago

A krypton laser produces a cylindrical red laser beam 2.40 mm in diameter with 1.70 W of power. What is the light intensity 1.76

marta [7]

Answer:

$I=3.75\times 10^5 W/m^2$

Explanation:

Given that

Diameter of laser beam d= 2.4 mm

Radius of laser beam r= 1.2 mm

Power P =1.7 W

We know that intensity(I) of laser beam given as follows

$I=\dfrac{P}{\pi r^2}$

Now by putting the values

$I=\dfrac{P}{\pi r^2}$

$I=\dfrac{1.7}{\pi \times 0.0012^2}$

So

$I=3.75\times 10^5 W/m^2$

So the intensity at 1.76 m away from laser

$I=3.75\times 10^5 W/m^2$

5 0

3 years ago

A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of

777dan777 [17]

Answer:

The correct answer will be:

(a) 27.3 m/s

(b) 3.8 s

Explanation:

According to the question:

Acceleration,

$a= 4.2 \ m/s^2$

Time,

$t = 6.5 \ s$

(a)

The gazelles top speed will be:

⇒ $V_{max} = at$

$=4.2\times 6.5$

$=27.3 \ m/s$

or,

$= 27 \ m/s$

(b)

As we know,

s = 30 m

Now,

⇒ $s = \frac{1}{2} at^2$

or,

⇒ $t=\sqrt{\frac{2s}{a} }$

On putting the given values, we get

$=\sqrt{\frac{2\times 30}{4.2} }$

$=\sqrt{\frac{60}{4.2} }$

$=3.78 \ s$

or,

$=3.8 \ s$

5 0

3 years ago

1. Three confused sled dogs are trying to pull a sled across the Alaskan snow. Tim pulls east with a force of 42 N; Sam also pul

Bumek [7]

Answer:

Explanation:

According to the statement, three confused sleigh dogs are trying to pull a sled across the Alaskan snow.

Forces in same direction gets added , so 35N + 42N=77N and the Net Force is 77N -53N as it is acting in opposite direction.

Net force is 25N in east to the maximum without any hassle.

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thankyou : )

6 0

3 years ago