Answer:
0.00004666N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
So lets say that the power absorbed
Will be = Intensity x Area
Which Is = 1.4 x 10^3 x(10)
So
14000 Watt = 14 kWatt
However we know that radiation pressure is equal to
time-averaged intensity all over the speed of light in free space
So
P = (1.4 x 1000)/c
But
F= P x A
So
((1.4 x 1000)/(3 x1 0^8)) x 10
Which is
=0.000046666N
Explanation:
Answer: Option 3.
Explanation:
Formula for kinetic energy is
K.E = (1 / 2) * (m * v ^ 2)
Assuming mass to be constant,
We can see that K.E is proportional to v^2.
It means that when you substitute the value of velocity in v, kinetic energy increases with v^2.
Option 1 and 2 are eliminated because the relationship between kinetic energy and velocity in the graph is shown as linear. We already know from formula that the relationship is not linear.
Option 4 is incorrect because kinetic energy must be zero when velocity is zero. This graph shows kinetic energy is becoming infinite as velocity tends to 0.
So option 3 is correct answer.
The impulse experienced is -18,000 kg m/s
Explanation:
The impulse exerted on an object is equal to the change in momentum of the object. Mathematically:
where
m is the mass of the object
v is the final velocity of the object
u is the initial velocity
is the change in momentum
I is the impulse
In the collision in this problem,
m = 1300 kg is the mass of the car
u = 11 m/s is the initial velocity
v = -2.5 m/s is the final velocity (negative, since it is in the opposite direction)
Substituting, we find
So the closest choice is
-18,000 kg m/s
Learn more about impulse and change in momentum:
brainly.com/question/9484203
#LearnwithBrainly
Answer:
66.98 db
Explanation:
We know that
L_T= Total signal level in db
n= number of sources
L_S= signal level from signal source.
= 66.98 db
Answer:
If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)
The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite direction to the incident ray.
