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ycow [4]
3 years ago
10

What is the horizontal component of a ball thrown at a 27 degree angle at 16 m/s?

Physics
1 answer:
Airida [17]3 years ago
6 0

Answer:

14.25 m/s

Explanation:

In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.

It can be given by :

v_x=v\cos\theta\\\\=16\times \cos(27)\\\\=14.25\ m/s

So, the horizontal component of the ball is 14.25 m/s.

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How does the mass of an object change the gravitational pull on two objects in a system? How does the distance between objects i
LuckyWell [14K]

Answer:The greater the mass, there greater then gravitational pull on their objects.

There greater the distance,the lower the gravitational pull between the object

Explanation:

Gravitational pull(force) is directly proportional to the products Of The masses. therefore if the mass increase,the gravitational pull(force) also increases.

Gravitational pull(force) is inversely proportional to distance.if the distance between the objects increases,the gravitational pull(force) decreases .

4 0
3 years ago
What is the current flowing through this circuit? Look at the picture!
castortr0y [4]

Answer:

Explanation:

It doesnt show

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3 years ago
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what is the ratio of electrostatic force and the gravitational force between a proton and an electron?
Vadim26 [7]

Answer:

Explanation:

electron attraction between electron and nucleus = centripetal force of the orbiting electron

In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.

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4 years ago
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3. A car has a mass of 1000kg. What is its weight?<br><br> A) 9.81x10 ^ 3N<br> B) 1.89x10 ^ 3N
Strike441 [17]

Answer

A

Explanation:

Weight = Mass x Acceleration due to gravity

Weight = 1000 x 9.81

= 9810 or 9.81x10^ 3

6 0
3 years ago
Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends
lesya692 [45]

Answer:

0.00384 kg/m

Explanation:

The fundamental frequency of string waves is given by

f=\frac{1}{2L}\sqrt{\frac{F}{\mu}}

For some tension (F) and length (L)

f\propto\frac{1}{\mu}

Fundamental frequency of G string

f_G=196\ Hz

Fundamental frequency of E string

f_E=659.3\ Hz

Linear mass density of E string is

\mu_E=3.4\times 10^{-4}\ kg/m

So,

\frac{F_G}{F_E}=\sqrt{\frac{\mu_E}{\mu_G}}\\\Rightarrow \frac{F_G^2}{F_E^2}=\frac{\mu_E}{\mu_G}\\\Rightarrow \mu_G=3.4\times 10^{-4}\times \frac{659.3^2}{196^2}\\\Rightarrow \mu_G=0.00384\ kg/m

The linear density of the G string is 0.00384 kg/m

4 0
3 years ago
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