What is the horizontal component of a ball thrown at a 27 degree angle at 16 m/s?
1 answer:
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Answer:
The distance between them, x = 5809.47 m
Explanation:
Given,
The average weight of a human, w = 600 N
The charge carried by the humans, q = 1.5 C
If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,
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Where,
= 9 x 10⁹ N m² C⁻²
Therefore
x² = 9 x 10⁹ X 1.5² / 600
= 33750000
x = 5809.46 m
Hence, the distance between the humans should be, x = 5809.47 m
Angles will probably be 96° 35° and 49°
I tried to explain it with the working out, just re arrange the cosine rule for angles instead of side lengths.
if you need it explaining at all just message me :)
hoped it helped
I tried to explain it with the working out, just re arrange the cosine rule for angles instead of side lengths.
if you need it explaining at all just message me :)
hoped it helped