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2 years ago

What is the horizontal component of a ball thrown at a 27 degree angle at 16 m/s?

Physics

1 answer:

Airida [17]2 years ago

6 0

Answer:

14.25 m/s

Explanation:

In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.

It can be given by :

$v_x=v\cos\theta\\\\=16\times \cos(27)\\\\=14.25\ m/s$

So, the horizontal component of the ball is 14.25 m/s.

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Explanation:

(a)

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Where,

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Where,

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3 years ago

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Hope this helps :)

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