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Kitty [74]
4 years ago
4

Which best explains why one laser beam might appear blue and another laser beam might appear red?

Physics
2 answers:
dlinn [17]4 years ago
6 0

Answer: One laser beam might appear blue and another laser beam might appear red because each laser beam is made up of one specific wavelength of light.

Explanation :

A laser is simply defined as <em>Light Amplification by Stimulated Emission of Radiation</em>.  

Laser light is composed of light of one color only. This means that laser light emits light of single frequency or wavelength. That's why one laser beam appears blue and another laser beam appears red.

So, the correct option is (d) " Each laser beam is made up of one specific wavelength of light ".

FrozenT [24]4 years ago
3 0
Each laser beam is made up of one specific wavelength of light.
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Kate's recollection of these different events along her life best exemplifies the use of her episodic memory.

<h3>What is episodic memory?</h3>

The term episodic memory makes reference to conscious personal background experiences that were collected along life.

Episodic memory is also defined as the collection of all life-day experiences collected by a person.

The episodic memory may be, for example, the first day when a person drove his/her car or a bike.

Learn more about episodic memory here:

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While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th
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Answer:

Explanation:

From the given information:

radius = 15 m

Time T = 23 s

a) Speed (v) = \dfrac{2 \pi r}{T}

v = \dfrac{2\times \pi \times 15}{23}

v = 4.10 m/s

b) The magnitude of the acceleration is:

a = \dfrac{v^2}{r} \\ \\ a = \dfrac{(4.10)^2}{15}

a = 1.12 m/s²

c) True weight = mg

Apparent weight = normal force

From the top;

the normal force = upward direction,

weight is downward as well as the acceleration.

true weight - normal force = ma  

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\dfrac{apparent \ weight}{true \  weight} = \dfrac{(mg - ma)}{(mg)}

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d)

From the bottom;

acceleration is upward, so:

apparent weight - true weight = ma

apparent weight = true weight + ma

\dfrac{apparent \ weight }{true \ weight} =\dfrac{ mg + ma}{mg}

\dfrac{apparent \ weight }{true \ weight} =1+ \dfrac{a}{g} \\ \\ = 1 + \dfrac{1.12}{9.8}

= 1 + \dfrac{1.12}{9.8} \\ \\

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3 years ago
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Any object would weigh twice as much on Jupiter as it would on Neptune.

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Effectus [21]

Answer:

PARABOLIC, EARTH, VERTICAL, INERTIAL ang PHYSICAL LAWS

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In this exercise you are asked to complete the missing words.

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