Nothing works if Switch-3 is open.
-- None
-- A, E, F, G
-- None
-- A, B, E, F, G
-- A, C, D, E, F, G (everything except B)
First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m
Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m
The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m
Answer:
It can do work on an object by moving it or changing it.
Explanation:
Brainliest?
True True False True False False True I hope I helped on the first few
