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algol13
3 years ago
7

What did Bohi's model of the dom inchide that Ruthextends model did not have

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Electrons revolves around the nucleus in a fixed orbits with fixed energy.

electron clouds.

Explanation:

Rutherford in his model of atom explained:

  • Maximum space inside the atom is empty.
  • Electron revolves around the the center called nucleus.
  • Nucleus contains the positive charge.

Bohr's in his model explained that:

  • Electrons revolves around the nucleus in a fixed orbit named as shells.
  • Each orbits or shells has fixed amount of energy and size.

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How does the table show that the balloon went downwards ?
o-na [289]

Answer:

I am going to guess it shows that the balloon is going downwards because the speed of rise is in the negatives for the last 2.

6 0
3 years ago
Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to str
Vlad [161]

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact is 77.19°

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

g = Acceleration due to gravity = 9.81 m/s²

u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m

The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, v_y, of the package just before landing is given by the relation;

v_y² = u² + 2·g·h

u = 0 m/s

∴ v_y² = 0 + 2×9.81×1500 = 29430 m²/s²

v_y = √29430  = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact, θ, is given as follows;

tan \theta = \dfrac{v_y}{v_x}  = \dfrac{171.55}{39.0 } = 4.4

∴ θ = tan⁻¹(4.4) = 77.19°.

6 0
4 years ago
The most frequent compulsion that is exhibited in obsessive-compulsive disorder is
Vinil7 [7]
The most frequent compulsion that is exhibited in obsessive compulsive disorder is cleansing 
6 0
3 years ago
HELP!! ALL MY POINTS WILL BE GIVEN
Marta_Voda [28]

Answer:

-6 m/s^2

Explanation:

30 - 90 = -60

-60 / 10 = -6

If acceleration was constant, it will be -6 m/s^2

5 0
2 years ago
Read 2 more answers
A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 x 106 meters, find the mass of
melisa1 [442]

Answer:

7.36 × 10^22 kg

Explanation:

Mass of the man = 90kg

Weight on the moon = 146N

radius of the moon =1.74×10^6

Weight =mg

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From the law of gravitational force

g = GM/r^2

Where G = 6.67 ×10^-11

M = gr^2/G

M= 1.62 × (1.74×10^6)^2/6.67×10^-11

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=0.735×10^23

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3 0
3 years ago
Read 2 more answers
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