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Answer:
128g of Li, will react in this reaction
Explanation:
Before to start working, we need the reaction:
N₂ and Li react, in order to produce Li₃N (lithium nitride)
N₂ + 6Li → 2Li₃N
1 mol of nitrogen reacts with 6 moles of lithium
We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles
1 mol of N₂ reacts with 6 mol of Li
Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li
We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g
Answer:
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Explanation:
Radioactive material undergoes first order dissociation kinetics.
For 1st order system,
k = 0.693 / t1/2
where, t 1/2 = half-life of the radioactive disintegration process.
Given that, t 1/2 = <span>73.83 days
Therefore, k = 0.009386 day-1
Also, for 1st order reaction,
k = </span>

Given that, Co = initial concentration of <span>Iridium-192 = 100 g
Therefore, </span>0.009386 =

On rearranging we get,
Ct = 100
Answer: Ct = 100

equation approximates the amount of Iridium-192 present after t days