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Usimov [2.4K]
3 years ago
11

Please help help help help

Chemistry
1 answer:
Anni [7]3 years ago
3 0

Answer:

50000 dollars or 5 e5

Explanation:

Mr. Garibay has 5.0 * 10^4 dollars in his bank.

Scientific notation represents the data in the format of expanded number or with e character.

For instance, 5.0 * 10^4 dollars = 50000 dollars or 5 e5

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Masteriza [31]

Answer:

i think it is true

Explanation:

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4 0
3 years ago
Read 2 more answers
7. A. How many moles of Calcium hydroxide (CaOH2) are needed to completely react with 14.5 mol of Phosphoric acid (H3PO4)?
Artyom0805 [142]

Answer:

moles of calcium hydroxide= 21.75 mol

a) 43.5 mol

b) 7.25 mol

Explanation:

Please see the attached picture for the full solution.

6 0
3 years ago
What must be true about a substance that is being dissolved by water?
Elena-2011 [213]
Water is always the solvent
7 0
4 years ago
Molar mass of lead(ll)chloride
Fiesta28 [93]
I look for your answer 278.1 g/mol I hope this help
5 0
3 years ago
Copper has two naturally occurring isotopes with atomic masses of 62.9296 u () and 64.9278 u (). The atomic mass of copper is 63
natta225 [31]

Answer:

The abundance of first isotope is 69.15 %

The abundance of second isotope is 30.85 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope:

% = x %

Mass = 62.9296 u

For second isotope:

% = 100  - x  

Mass = 64.9278 u

Given, Average Mass = 63.546 u

Thus,  

63.546=\frac{x}{100}\times {62.9296}+\frac{100-x}{100}\times {64.9278}

Solving for x, we get that:

x = 69.15 %

<u>The abundance of first isotope is 69.15 %</u>

<u>The abundance of second isotope is 100 - 69.15 % = 30.85 %</u>

4 0
4 years ago
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