In the modern periodic table when elements are arranged according to their atomic number.
The element is TELLURIUM. Tellurium has atomic number 52 with the electronic configuration of [Kr] 4d10 5s2 5p4. The element belongs to group 16 elements on the periodic table. It exhibits various oxidation states: +2, +4, +6, and -2. +4 is its most common oxidation state.
Answer:
C, Moves energy.
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Explanation:
Not only did outermost electron determine the valence electron, but also <em>periodic</em><em> </em><em>table</em><em>.</em><em> </em>whatever group they fall into in periodic table each valence electrons present in a particular atom e.g K and Ca belong to group 1 and 2 respectively and k has 1 and Ca have 2 in each outermost electron
Answer:
The right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"
Explanation:
Catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy Eₐ (i.e. by changing the reaction pathway), which Catalyst is not consumed in the catalyzed reaction and can continue to act repeatedly.
From the attached figure one can see that the path way A-C-D has different pathway and lower activation energy (Eₐ) than the pathway A-B-D, this means that the pathway A-C-D is a catalyzed pathway and it is faster than A-B-D.
So, the right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"